Chapter 4, Problem 4.41PAE

Methanol, CH₃OH, is used in racing cars because it is a clean-burning fuel. It can be made by this reaction:

   $\text{CO}\left(\text{g}\right)+{\text{2 H}}_{\text{2}}\left(\text{g}\right)\to {\text{ CH}}_{\text{3}}\text{OH}\left(\text{l}\right)$

What is the percentage yield if $\text{5}.0\times \text{ 1}{0}^{\text{3}}{\text{g H}}_{\text{2}}$ reacts with excess CO to form $\text{3}.\text{5 }\times \text{ 1}{0}^{\text{4}}{\text{g CH}}_{\text{3}}\text{OH}$ ?