Pheromone G of the maize stalk borer, chilo partelus, can be synthesized based on the partial scheme shown below. Complete the scheme by identifying the structures of the intermediate compounds A, B, C, D, E, F and pheromone G. Indicate stereochemistry where relevant
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Pheromone G of the maize stalk borer, chilo partelus, can be synthesized based on the partial scheme shown below. Complete the scheme by identifying the structures of the intermediate compounds A, B, C, D, E, F and pheromone G. Indicate stereochemistry where relevant
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- Alpha-phellandrene, C₁0H16, is a pleasant-smelling chiral compound that may be obtained from the leaves of eucalyptus trees. It has the molecular formula C₁0H16 and a UV absorption maximum at 263 nm. On hydrogenation with a palladium catalyst, an achiral hydrocarbon with the formula C10H20 is obtained. Ozonolysis of alpha-phellandrene, followed by treatment with zinc and acetic acid, produces the following two compounds: CHIC-CH HOCHSCHICH CH(CH3)2 Propose a structure for alpha-phellandrene.Alpha-phellandrene, C₁0H₁6, is a pleasant-smelling chiral compound that may be obtained from the leaves of eucalyptus trees. It has the molecular formula C₁0H16 and a UV absorption maximum at 263 nm. On hydrogenation with a palladium catalyst, an achiral hydrocarbon with the formula C₁0H20 is obtained. Ozonolysis of alpha-phellandrene, followed by treatment with zinc and acetic acid, produces the following two compounds: 0 || CH3C-CH 0 || ● Propose a structure for alpha-phellandrene. (+ || HCCH₂CHCH I CH(CH3)2 • You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. n [ ]# ?Identify products A and B from the given 1H NMR data. Treatment of acetone [(CH3)2C=O] with dilute aqueous base forms B. Compound B exhibits four singlets in its 1H NMR spectrum at 1.3 (6 H), 2.2 (3 H), 2.5 (2 H), and 3.8 (1H) ppm. What is the structure of B?
- (c) In the reaction scheme below, compound D is a bicyclic aromatic heterocycle that is prepared via intermediate C. Compound D has a molecular formula of C10H11N and reacts with acetone to form E, which has a molecular formula of C23H26N2. Draw the structures of C, D and E and provide mechanisms for their formation. N CH₂CH3 + Br- CH3 C NaOH (aq) D H3C CH3 H₂SO4 (aq) EDeduce the structures of compounds A and B, two of the major components of jasmine oil, from the given data. Compound A: C9H10O2; IR absorptions at 3091–2895 and 1743 cm-1; 1H NMR signals at 2.06 (singlet, 3 H), 5.08 (singlet, 2 H), and 7.33 (broad singlet, 5 H) ppm. Compound B: C14H12O2; IR absorptions at 3091–2953 and 1718 cm-1; 1H NMR signals at 5.35 (singlet, 2 H) and 7.26–8.15 (multiplets, 10 H) ppm.Identify the major product(s) of the following reactions. Include stereochemistry. (a) (b) (c) Br NaOEt NaOEt NaOEt
- Two isomers, A and B, of molecular formula C5H8 undergo catalytic hydrogenation with hydrogen gas and palladium on carbon to form the same C5H10 product. On ozonolysis followed by treatment with hydrogen peroxide (H₂O2), isomer A gave a product of molecular formula C5H8O4 that has two carboxylic acid groups in it whereas isomer B gave a product of molecular formula C5H8O3 that contains a carboxylic acid group and a ketone group. Which of the following isomeric pairs best match this data? a. Isomer A is cyclopentene and isomer is 1-pentyne O b. Isomer A is cyclopentene and isomer B is 1-methylcyclobutene c. Isomer A is cyclopentene and isomer B is 3-methylcyclobutene d. Isomer A is 1-methylcyclobutene and isomer B is 3-methylcyclobuteneTwo isomers, A and B, of molecular formula C5H8 undergo catalytic hydrogenation with hydrogen gas and palladium on carbon to form the same C5H10 product. On ozonolysis followed by treatment with hydrogen peroxide (H2O2), isomer A gave a product of molecular formula C5H8O4 that has two carboxylic acid groups in it whereas isomer B gave a product of molecular formula C5H8O3 that contains a carboxylic acid group and a ketone group. What is the isometric pair of A and B that corresponds?Two isomers, A and B, of molecular formula C5H8 undergo catalytic hydrogenation with hydrogen gas and palladium on carbon to form the same C5H10 product. On ozonolysis followed by treatment with hydrogen peroxide (H2O2), isomer A gave a product of molecular formula C5H8O4 that has two carboxylic acid groups in it whereas isomer B gave a product of molecular formula C5H8O3 that contains a carboxylic acid group and a ketone group. Which of the following isomeric pairs best match this data?
- Treatment of compound E (molecular formula C4H8O2) with excess CH3CH2MgBr yields compound F (molecular formula C6H14O) after protonation with H2O. E shows a strong absorption in its IR spectrum at 1743 cm-1. F shows a strong IR absorption at 3600–3200 cm-1. The 1H NMR spectral data of E and F are given. What are the structures of E and F?Compound E signals at 1.2 (triplet, 3 H), 2.0 (singlet, 3 H), and 4.1 (quartet, 2 H) ppmCompound F signals at 0.9 (triplet, 6 H), 1.1 (singlet, 3 H), 1.5 (quartet, 4 H), and 1.55 (singlet, 1 H) ppmAn unknown compound A of molecular formula C10H18O reacts with H2SO4 to form two compounds (B and C)of molecular formula C10H16. B and C both react with H2 in the presence of Pd-C to form decalin. Ozonolysis of B forms D, and ozonolysis of C forms a diketone E of molecular formula C10H16O2. Identify the structures of compounds A, B, C, and E.-Ocimene is a pleasant-smelling hydrocarbon found in the leaves of certain herbs. It has the molecular formula C10H16 and a UV absorption maximum at 232 nm. On hydrogenation with a palladium catalyst, 2,6-dimethyloctane is obtained. Ozonolysis of -ocimene, followed by treatment with zinc and acetic acid, produces the following four fragments: (a) How many double bonds does -ocimene have? (b) Is -ocimene conjugated or nonconjugated? (c) Propose a structure for -ocimene. (d) Write the reactions, showing starting material and products.
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