Let X be a negative binomial random variable with parameters n and p, and let Y be a binomial random variable with parameters n and p. Show that P { X > n } = P { Y < r } Hint: Either one could attempt an analytical proof of the preceding equation, which is equivalent to proving the identity ∑ i = n + 1 ∞ ( i − 1 r − 1 ) p r ( 1 − p ) i − r = ∑ i = 0 r − 1 ( n i ) × p i ( 1 − p ) n − i or one could attempt a proof that uses the probabilistic interpretation of these random variables. That is, in the latter case, start by considering a sequence of independent trials having a common probability p of success. Then try to express the events { X > n } and { Y < r } in terms of the outcomes of this sequence.
Let X be a negative binomial random variable with parameters n and p, and let Y be a binomial random variable with parameters n and p. Show that P { X > n } = P { Y < r } Hint: Either one could attempt an analytical proof of the preceding equation, which is equivalent to proving the identity ∑ i = n + 1 ∞ ( i − 1 r − 1 ) p r ( 1 − p ) i − r = ∑ i = 0 r − 1 ( n i ) × p i ( 1 − p ) n − i or one could attempt a proof that uses the probabilistic interpretation of these random variables. That is, in the latter case, start by considering a sequence of independent trials having a common probability p of success. Then try to express the events { X > n } and { Y < r } in terms of the outcomes of this sequence.
Solution Summary: The author explains that for a negative binomial random variable with parameters PX>n=PY, more than n variables should be required.
Let X be a negative binomial random variable with parameters n and p, and let Y be a binomial random variable with parameters n and p. Show that
P
{
X
>
n
}
=
P
{
Y
<
r
}
Hint: Either one could attempt an analytical proof of the preceding equation, which is equivalent to proving the identity
∑
i
=
n
+
1
∞
(
i
−
1
r
−
1
)
p
r
(
1
−
p
)
i
−
r
=
∑
i
=
0
r
−
1
(
n
i
)
×
p
i
(
1
−
p
)
n
−
i
or one could attempt a proof that uses the probabilistic interpretation of these random variables. That is, in the latter case, start by considering a sequence of independent trials having a common probability p of success. Then try to express the events
{
X
>
n
}
and
{
Y
<
r
}
in terms of the outcomes of this sequence.
Among a student group 54% use Google Chrome, 20% Internet Explorer, 10% Firefox, 5% Mozilla, and the rest use Safari. What is the probability that you need to pick 7 students to find 2 students using Google Chrome? Report answer to 3 decimals.
Samples of rejuvenated mitochondria are mutated (defective) with a probability 0.13. Find the probability that at most one sample is mutated in 10 samples. Report answer to 3 decimal places.
The same final exam of the astronomy course was given to two groups of students. The maximum number of points that a student can score is 100. The first group consisted of a random sample of 10 students who were taught by Professor A. Students from the first group obtained the following results:
87 88 91 88 86 92 81 93 73 99
The second group consisted of a random sample of 9 students who were taught by Professor B. Students from the second group obtained the following results:
74 74 79 97 67 88 86 83 78
Compute the mean squares of between-group variability, MSBET. Round your answer to two decimal places.
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