
Concept explainers
The random variable X is said to follow the distribution of Benford’s Law if
It has been shown to be a good fit for the distribution of the first digit of many real life data values.
a. Verify that the preceding is a
b. Find

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- 8.4.6 Information on a packet of seeds claims that 93% of them will germinate. Of the 200 seeds that were planted, only 180 germinated. a. Find a 95% confidence interval for the true proportion of seeds that germinate based on this sample. b. Does this seem to provide evidence that the claim is wrong? 8.6.1 Consider the tire-testing data described in Exercise 8.2.3. Compute a 95% prediction interval on the life of the next tire of this type tested under conditions that are similar to those employed in the original test. Compare the length of the prediction interval with the length of the 95% CI on the population mean.arrow_forwardAnswer questions 8.3.1 and 8.3.2 respectivelyarrow_forward8.2.7 The brightness of a television picture tube can be evaluated by measuring the amount of current required to achieve a particular brightness level. A sample of 10 tubes results in x = 317.2 and s = 15.7. Find (in microamps) a 99% confidence interval on mean current required. State any necessary assumptions about the underlying distribution of the data. 8.2.8 An article in the Journal of Composite Materials (December 1989, Vol. 23(12), pp. 1200–1215) describes the effect of delamination on the natural frequency of beams made from composite laminates. Five such delaminated beams were subjected to loads, and the resulting frequencies (in hertz) were as follows: 230.66, 233.05, 232.58, 229.48, 232.58 Check the assumption of normality in the population. Calculate a 90% two-sided confidence interval on mean natural frequency.arrow_forward
- 8.2.5 An article in Obesity Research [“Impaired Pressure Natriuresis in Obese Youths” (2003, Vol. 11, pp. 745–751)] described a study in which all meals were provided for 14 lean boys for three days followed by one stress test (with a video-game task). The average systolic blood pressure (SBP) during the test was 118.3 mm HG with a standard deviation of 9.9 mm HG. Construct a 99% one-sided upper confidence interval for mean SBP. 8.2.6 An article in Medicine and Science in Sports and Exercise [“Maximal Leg-Strength Training Improves Cycling Economy in Previously Untrained Men” (2005, Vol. 37, pp. 131–136)] studied cycling performance before and after 8 weeks of leg-strength training. Seven previously untrained males performed leg-strength training 3 days per week for 8 weeks (with four sets of five replications at 85% of one repetition maximum). Peak power during incremental cycling increased to a mean of 315 watts with a standard deviation of 16 watts. Construct a 95% confidence…arrow_forwardthey take? 8.1.13 WP GO Tutorial An article in the Journal of Agricultural Science ["The Use of Residual Maximum Likelihood to Model Grain Quality Characteristics of Wheat with Variety, Climatic and Nitrogen Fertilizer Effects” (1997, Vol. 128, pp. 135–142)] investigated means of wheat grain crude protein content (CP) and Hagberg falling number (HFN) surveyed in the United Kingdom. The analysis used a variety of nitrogen fertilizer applications (kg N/ha), temperature (°C), and total monthly rainfall (mm). The following data below describe temperatures for wheat grown at Harper Adams Agricultural College between 1982 and 1993. The temperatures measured in June were obtained as follows: 15.2 14.2 14.0 12.2 14.4 12.5 14.3 14.2 13.5 11.8 15.2 Assume that the standard deviation is known to be σ = 0.5. a. Construct a 99% two-sided confidence interval on the mean temperature. b. Construct a 95% lower-confidence bound on the mean temperature. c. Suppose that you wanted to be 95% confident that…arrow_forward8.1.1 WP For a normal population with known variance σ², answer the following questions: - a. What is the confidence level for the interval x — 2.140/ √√n≤≤+2.140/√√n?arrow_forward
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- 8.2.3 A research engineer for a tire manufacturer is investigating tire life for a new rubber compound and has built 16 tires and tested them to end-of-life in a road test. The sample mean and standard deviation are 60,139.7 and 3645.94 kilometers. Find a 95% confidence interval on mean tire life. 8.2.4 Determine the t-percentile that is required to construct each of the following one-sided confidence intervals: a. Confidence level = 95%, degrees of freedom = 14 b. Confidence level = 99%, degrees of freedom = 19 c. Confidence level = 99.9%, degrees of freedom = 24arrow_forward8.1.6The yield of a chemical process is being studied. From previous experience, yield is known to be normally distributed and σ = 3. The past 5 days of plant operation have resulted in the following percent yields: 91.6, 88.75, 90.8, 89.95, and 91.3. Find a 95% two-sided confidence interval on the true mean yield. 8.1.7 .A manufacturer produces piston rings for an automobile engine. It is known that ring diameter is normally distributed with σ = 0.001 millimeters. A random sample of 15 rings has a mean diameter of x = 74.036 millimeters. a. Construct a 99% two-sided confidence interval on the mean piston ring diameter. b. Construct a 99% lower-confidence bound on the mean piston ring diameter. Compare the lower bound of this confi- dence interval with the one in part (a).arrow_forward8.1.2 .Consider the one-sided confidence interval expressions for a mean of a normal population. a. What value of zα would result in a 90% CI? b. What value of zα would result in a 95% CI? c. What value of zα would result in a 99% CI? 8.1.3 A random sample has been taken from a normal distribution and the following confidence intervals constructed using the same data: (38.02, 61.98) and (39.95, 60.05) a. What is the value of the sample mean? b. One of these intervals is a 95% CI and the other is a 90% CI. Which one is the 95% CI and why?arrow_forward
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