Explanation Given: Inlet temperature of water is 60 F . Inlet pressure of water is 60 lbf/in 2 . Mass flow arte of air is 4 lbm/s . Inlet temperature of air is 1400 R . Outlet temperature of air is 680 R . Pressure of air is 150 lbf/in 2 . Concept used: Write the expression for heat gain by water. Q = m ˙ w [ C p , w ( T w , o − T w , i ) + h f g ] ..... (1) Here, Q is the heat gain by water, m ˙ is the mass flow rate of water, C p , w is the specific heat of water, T w , i is the inlet temperature of water, h f g is the specific enthalpy of evaporation and T w , o is the outlet temperature of water. Write the expression for heat lost by air. Q = m ˙ a C p , a ( T a , i − T a , o ) ..... (2) Here, m ˙ a is the mass flow rate of air, C p , a is the specific heat of air, T a , i is the inlet temperature of air and T a , o is the outlet temperature of air. The heat lost by the air is gained by the water. Substitute m ˙ a C p , a ( T a , i − T a , o ) for Q in equation (1). m ˙ a C p , a ( T a , i − T a , o ) = m ˙ w [ C p , w ( T w , o − T w , i ) + h f g ] Rearrange above expression for m ˙ w . m ˙ w = m ˙ a C p , a ( T a , i − T a , o ) [ C p , w ( T w , o − T w , i ) + h f g ]

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Chapter 4, Problem 4.147EP

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The flow rate of water.

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Chapter 4, Problem 4.146EP

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EBK FUNDAMENTALS OF THERMODYNAMICS, ENH

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