The comparison between Figure 4-47 and 4-49 is to be done and the reason for the difference between them is to be stated. The given statement about B 2 is to be rationalized. The reason for σ 2 p to be lower in energy than the π 2 p orbital is to be stated. The reason for not using diatomic oxygen for check this difference is to be sated. Concept introduction: When the atomic orbitals overlap with each other in the region where density of electrons is high, then molecular orbitals are formed. Overlap of the atomic orbitals determines the efficiency of the interaction between the atomic orbitals. Energy of bonding molecular orbitals is less than the nonbonding molecular orbitals. To determine: The comparison between Figure 4-47 and 4-49, the reason for the difference between them, the rationalization of the given statement about B 2 , reason for σ 2 p to be lower in energy than the π 2 p orbital and reason for not using diatomic oxygen for check this difference.
The comparison between Figure 4-47 and 4-49 is to be done and the reason for the difference between them is to be stated. The given statement about B 2 is to be rationalized. The reason for σ 2 p to be lower in energy than the π 2 p orbital is to be stated. The reason for not using diatomic oxygen for check this difference is to be sated. Concept introduction: When the atomic orbitals overlap with each other in the region where density of electrons is high, then molecular orbitals are formed. Overlap of the atomic orbitals determines the efficiency of the interaction between the atomic orbitals. Energy of bonding molecular orbitals is less than the nonbonding molecular orbitals. To determine: The comparison between Figure 4-47 and 4-49, the reason for the difference between them, the rationalization of the given statement about B 2 , reason for σ 2 p to be lower in energy than the π 2 p orbital and reason for not using diatomic oxygen for check this difference.
Solution Summary: The author analyzes the comparison between Figures 4-47 and 4-49 to determine the reason for the difference between them.
Interpretation: The comparison between Figure 4-47 and 4-49 is to be done and the reason for the difference between them is to be stated. The given statement about
B2 is to be rationalized. The reason for
σ2p to be lower in energy than the
π2p orbital is to be stated. The reason for not using diatomic oxygen for check this difference is to be sated.
Concept introduction: When the atomic orbitals overlap with each other in the region where density of electrons is high, then molecular orbitals are formed. Overlap of the atomic orbitals determines the efficiency of the interaction between the atomic orbitals.
Energy of bonding molecular orbitals is less than the nonbonding molecular orbitals.
To determine: The comparison between Figure 4-47 and 4-49, the reason for the difference between them, the rationalization of the given statement about
B2 , reason for
σ2p to be lower in energy than the
π2p orbital and reason for not using diatomic oxygen for check this difference.
R lactam or lactone considering as weak acid or weak base and why
81. a. Propose a mechanism for the following reaction:
OH
CH2=CHCHC=N
b. What is the product of the following reaction?
HO
H₂O
N=CCH2CH2CH
OH
HO
CH3CCH=CH2
H₂O
C=N
82. Unlike a phosphonium ylide that reacts with an aldehyde or a ketone to form an alkene a sulfonium ulia
For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check
the appropriate box.
Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below.
Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions
- just focus on the first stable product you expect to form in solution.
?
NH2
MgBr
Will the first product that forms in this reaction
create a new CC bond?
○ Yes
○ No
MgBr
?
Will the first product that forms in this reaction
create a new CC bond?
O Yes
O No
Click and drag to start drawing a
structure.
:☐
G
x
c
olo
Ar
HE
Chapter 4 Solutions
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell