a. Draw three constitutional isomers with molecular formula C 3 H 8 O. b. How many constitutional isomers can you draw for C 4 H 10 O?

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Answer 1

Textbook Question

Chapter 4, Problem 1P

a. Draw three constitutional isomers with molecular formula C₃H₈O.
b. How many constitutional isomers can you draw for C₄H₁₀O?

(a)

Expert Solution

Interpretation Introduction

Interpretation:

The three constitutional isomers of molecular formula C3H8O has to be drawn.

Concept introduction:

Constitutional isomers are having the same molecular formula and different bond connectivity between the atoms.

The general formula for an alkane is CnH2n+2.

Equation for finding constitutional isomers for a molecule

Answer to Problem 1P

EBK ESSENTIAL ORGANIC CHEMISTRY, Chapter 4, Problem 1P , additional homework tip 1

Explanation of Solution

The given molecular formula is C3H8O, it fulfils the general formula for an alkane CnH2n+2, so C3H8O contains only single bonds.

Therefore,

C3H8O can be an alcohol or ether.

The two possible alcohols are,

CH3−CH2−CH2−OH , EBK ESSENTIAL ORGANIC CHEMISTRY, Chapter 4, Problem 1P , additional homework tip 2

The possible ether is,

CH3−CH2−O−CH3

(b)

Expert Solution

Interpretation Introduction

Interpretation:

The numbers of constitutional isomers of molecular formula C4H10O has to be determined.

Concept introduction:

Constitutional isomers are having the same molecular formula and different bond connectivity between the atoms.

Answer to Problem 1P

The numbers of constitutional isomers of molecular formula C4H10O is 7

Explanation of Solution

The given molecular formula is C4H10O, it fulfils the general formula for an alkane CnH2n+2, so C4H10O contains only single bonds.

Therefore,

C4H10O can be an alcohol or ether.

There will be five alcohol isomers (due to four carbons) and two ether isomers.

Hence,

C4H10O have 7 constitutional isomers.

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Answer 2

Textbook Question

Chapter 4, Problem 1P

a. Draw three constitutional isomers with molecular formula C₃H₈O.
b. How many constitutional isomers can you draw for C₄H₁₀O?

(a)

Expert Solution

Interpretation Introduction

Interpretation:

The three constitutional isomers of molecular formula C3H8O has to be drawn.

Concept introduction:

Constitutional isomers are having the same molecular formula and different bond connectivity between the atoms.

The general formula for an alkane is CnH2n+2.

Equation for finding constitutional isomers for a molecule

Answer to Problem 1P

EBK ESSENTIAL ORGANIC CHEMISTRY, Chapter 4, Problem 1P , additional homework tip 1

Explanation of Solution

The given molecular formula is C3H8O, it fulfils the general formula for an alkane CnH2n+2, so C3H8O contains only single bonds.

Therefore,

C3H8O can be an alcohol or ether.

The two possible alcohols are,

CH3−CH2−CH2−OH , EBK ESSENTIAL ORGANIC CHEMISTRY, Chapter 4, Problem 1P , additional homework tip 2

The possible ether is,

CH3−CH2−O−CH3

(b)

Expert Solution

Interpretation Introduction

Interpretation:

The numbers of constitutional isomers of molecular formula C4H10O has to be determined.

Concept introduction:

Constitutional isomers are having the same molecular formula and different bond connectivity between the atoms.

Answer to Problem 1P

The numbers of constitutional isomers of molecular formula C4H10O is 7

Explanation of Solution

The given molecular formula is C4H10O, it fulfils the general formula for an alkane CnH2n+2, so C4H10O contains only single bonds.

Therefore,

C4H10O can be an alcohol or ether.

There will be five alcohol isomers (due to four carbons) and two ether isomers.

Hence,

C4H10O have 7 constitutional isomers.

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Answer 3

Textbook Question

Chapter 4, Problem 1P

a. Draw three constitutional isomers with molecular formula C₃H₈O.
b. How many constitutional isomers can you draw for C₄H₁₀O?

(a)

Expert Solution

Interpretation Introduction

Interpretation:

The three constitutional isomers of molecular formula C3H8O has to be drawn.

Concept introduction:

Constitutional isomers are having the same molecular formula and different bond connectivity between the atoms.

The general formula for an alkane is CnH2n+2.

Equation for finding constitutional isomers for a molecule

Answer to Problem 1P

EBK ESSENTIAL ORGANIC CHEMISTRY, Chapter 4, Problem 1P , additional homework tip 1

Explanation of Solution

The given molecular formula is C3H8O, it fulfils the general formula for an alkane CnH2n+2, so C3H8O contains only single bonds.

Therefore,

C3H8O can be an alcohol or ether.

The two possible alcohols are,

CH3−CH2−CH2−OH , EBK ESSENTIAL ORGANIC CHEMISTRY, Chapter 4, Problem 1P , additional homework tip 2

The possible ether is,

CH3−CH2−O−CH3

(b)

Expert Solution

Interpretation Introduction

Interpretation:

The numbers of constitutional isomers of molecular formula C4H10O has to be determined.

Concept introduction:

Constitutional isomers are having the same molecular formula and different bond connectivity between the atoms.

Answer to Problem 1P

The numbers of constitutional isomers of molecular formula C4H10O is 7

Explanation of Solution

The given molecular formula is C4H10O, it fulfils the general formula for an alkane CnH2n+2, so C4H10O contains only single bonds.

Therefore,

C4H10O can be an alcohol or ether.

There will be five alcohol isomers (due to four carbons) and two ether isomers.

Hence,

C4H10O have 7 constitutional isomers.

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Answer 4

Textbook Question

Chapter 4, Problem 1P

a. Draw three constitutional isomers with molecular formula C₃H₈O.
b. How many constitutional isomers can you draw for C₄H₁₀O?

(a)

Expert Solution

Interpretation Introduction

Interpretation:

The three constitutional isomers of molecular formula C3H8O has to be drawn.

Concept introduction:

Constitutional isomers are having the same molecular formula and different bond connectivity between the atoms.

The general formula for an alkane is CnH2n+2.

Equation for finding constitutional isomers for a molecule

Answer to Problem 1P

EBK ESSENTIAL ORGANIC CHEMISTRY, Chapter 4, Problem 1P , additional homework tip 1

Explanation of Solution

The given molecular formula is C3H8O, it fulfils the general formula for an alkane CnH2n+2, so C3H8O contains only single bonds.

Therefore,

C3H8O can be an alcohol or ether.

The two possible alcohols are,

CH3−CH2−CH2−OH , EBK ESSENTIAL ORGANIC CHEMISTRY, Chapter 4, Problem 1P , additional homework tip 2

The possible ether is,

CH3−CH2−O−CH3

(b)

Expert Solution

Interpretation Introduction

Interpretation:

The numbers of constitutional isomers of molecular formula C4H10O has to be determined.

Concept introduction:

Constitutional isomers are having the same molecular formula and different bond connectivity between the atoms.

Answer to Problem 1P

The numbers of constitutional isomers of molecular formula C4H10O is 7

Explanation of Solution

The given molecular formula is C4H10O, it fulfils the general formula for an alkane CnH2n+2, so C4H10O contains only single bonds.

Therefore,

C4H10O can be an alcohol or ether.

There will be five alcohol isomers (due to four carbons) and two ether isomers.

Hence,

C4H10O have 7 constitutional isomers.

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

(a)

Expert Solution

Interpretation Introduction

Interpretation:

The three constitutional isomers of molecular formula C3H8O has to be drawn.

Concept introduction:

Constitutional isomers are having the same molecular formula and different bond connectivity between the atoms.

The general formula for an alkane is CnH2n+2.

Equation for finding constitutional isomers for a molecule

Answer to Problem 1P

EBK ESSENTIAL ORGANIC CHEMISTRY, Chapter 4, Problem 1P , additional homework tip 1

Explanation of Solution

The given molecular formula is C3H8O, it fulfils the general formula for an alkane CnH2n+2, so C3H8O contains only single bonds.

Therefore,

C3H8O can be an alcohol or ether.

The two possible alcohols are,

CH3−CH2−CH2−OH , EBK ESSENTIAL ORGANIC CHEMISTRY, Chapter 4, Problem 1P , additional homework tip 2

The possible ether is,

CH3−CH2−O−CH3

(b)

Expert Solution

Interpretation Introduction

Interpretation:

The numbers of constitutional isomers of molecular formula C4H10O has to be determined.

Concept introduction:

Constitutional isomers are having the same molecular formula and different bond connectivity between the atoms.

Answer to Problem 1P

The numbers of constitutional isomers of molecular formula C4H10O is 7

Explanation of Solution

The given molecular formula is C4H10O, it fulfils the general formula for an alkane CnH2n+2, so C4H10O contains only single bonds.

Therefore,

C4H10O can be an alcohol or ether.

There will be five alcohol isomers (due to four carbons) and two ether isomers.

Hence,

C4H10O have 7 constitutional isomers.

Answer 8

(a)

Expert Solution

Interpretation Introduction

Interpretation:

The three constitutional isomers of molecular formula C3H8O has to be drawn.

Concept introduction:

Constitutional isomers are having the same molecular formula and different bond connectivity between the atoms.

The general formula for an alkane is CnH2n+2.

Equation for finding constitutional isomers for a molecule

Answer to Problem 1P

EBK ESSENTIAL ORGANIC CHEMISTRY, Chapter 4, Problem 1P , additional homework tip 1

Explanation of Solution

The given molecular formula is C3H8O, it fulfils the general formula for an alkane CnH2n+2, so C3H8O contains only single bonds.

Therefore,

C3H8O can be an alcohol or ether.

The two possible alcohols are,

CH3−CH2−CH2−OH , EBK ESSENTIAL ORGANIC CHEMISTRY, Chapter 4, Problem 1P , additional homework tip 2

The possible ether is,

CH3−CH2−O−CH3

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Interpretation Introduction

Interpretation:

The three constitutional isomers of molecular formula C3H8O has to be drawn.

Concept introduction:

Constitutional isomers are having the same molecular formula and different bond connectivity between the atoms.

The general formula for an alkane is CnH2n+2.

Equation for finding constitutional isomers for a molecule

Answer 13

Answer to Problem 1P

EBK ESSENTIAL ORGANIC CHEMISTRY, Chapter 4, Problem 1P , additional homework tip 1

Answer 14

Explanation of Solution

The given molecular formula is C3H8O, it fulfils the general formula for an alkane CnH2n+2, so C3H8O contains only single bonds.

Therefore,

C3H8O can be an alcohol or ether.

The two possible alcohols are,

CH3−CH2−CH2−OH , EBK ESSENTIAL ORGANIC CHEMISTRY, Chapter 4, Problem 1P , additional homework tip 2

The possible ether is,

CH3−CH2−O−CH3

Answer 15

(b)

Expert Solution

Interpretation Introduction

Interpretation:

The numbers of constitutional isomers of molecular formula C4H10O has to be determined.

Concept introduction:

Constitutional isomers are having the same molecular formula and different bond connectivity between the atoms.

Answer to Problem 1P

The numbers of constitutional isomers of molecular formula C4H10O is 7

Explanation of Solution

The given molecular formula is C4H10O, it fulfils the general formula for an alkane CnH2n+2, so C4H10O contains only single bonds.

Therefore,

C4H10O can be an alcohol or ether.

There will be five alcohol isomers (due to four carbons) and two ether isomers.

Hence,

C4H10O have 7 constitutional isomers.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Interpretation Introduction

Interpretation:

The numbers of constitutional isomers of molecular formula C4H10O has to be determined.

Concept introduction:

Constitutional isomers are having the same molecular formula and different bond connectivity between the atoms.

Answer 20

Answer to Problem 1P

The numbers of constitutional isomers of molecular formula C4H10O is 7

Answer 21

Explanation of Solution

The given molecular formula is C4H10O, it fulfils the general formula for an alkane CnH2n+2, so C4H10O contains only single bonds.

Therefore,

C4H10O can be an alcohol or ether.

There will be five alcohol isomers (due to four carbons) and two ether isomers.

Hence,

C4H10O have 7 constitutional isomers.

Answer 22

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a. Draw three constitutional isomers with molecular formula C 3 H 8 O. b. How many constitutional isomers can you draw for C 4 H 10 O?

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