Chapter 4, Problem 12QAP

Interpretation Introduction

(a)

Interpretation:

The molarity of 25.00 mL solution of iron(III) nitrate should be determined which reacts with 12.54 mL of 0.1488 M sodium carbonate.

Concept introduction:

Number of moles is equal to the ratio of given mass to the molar mass.

The mathematical expression is given by:

Number of moles = $\frac{\text{given mass}}{\text{molar mass}}$

Molarity is defined as the ratio of number of moles of solute to the volume of the solution in liters.

The mathematical expression is given by:

Molarity = $\frac{\text{moles of solute }}{\text{volume of solution in liters}}$

A solution of salt of metal when reacts with other solution to give products, the formula which is used to find the volume of either solution is given by:

${\text{M}}_{\text{1}}{\text{V}}_{\text{1}}{\text{=M}}_{\text{2}}{\text{V}}_{\text{2}}$

Where, M₁ and M₂ are molarity of the solution

V₁ and V₂ are volume of the solution

Interpretation Introduction

(b)

Interpretation:

The molarity of 25.00 mL solution of iron(III) nitrate should be determined which reacts with 7.58 g of potassium phosphate.

Concept introduction:

Number of moles is equal to the ratio of given mass to the molar mass.

The mathematical expression is given by:

Number of moles = $\frac{\text{given mass}}{\text{molar mass}}$

Molarity is defined as the ratio of number of moles of solute to the volume of the solution in liters.

The mathematical expression is given by:

Molarity = $\frac{\text{moles of solute }}{\text{volume of solution in liters}}$

A solution of salt of metal when reacts with other solution to give products, the formula which is used to find the volume of either solution is given by:

${\text{M}}_{\text{1}}{\text{V}}_{\text{1}}{\text{=M}}_{\text{2}}{\text{V}}_{\text{2}}$

Where, M₁ and M₂ are molarity of the solution

V₁ and V₂ are volume of the solution

Interpretation Introduction

(c)

Interpretation:

The molarity of 25.00 mL solution of iron(III) nitrate should be determined which reacts with 10.00 mL of 0.1573 M ${\text{Sr(OH)}}_{\text{2}}$.

Concept introduction:

Number of moles is equal to the ratio of given mass to the molar mass.

The mathematical expression is given by:

Number of moles = $\frac{\text{given mass}}{\text{molar mass}}$

Molarity is defined as the ratio of number of moles of solute to the volume of the solution in liters.

The mathematical expression is given by:

Molarity = $\frac{\text{moles of solute }}{\text{volume of solution in liters}}$

A solution of salt of metal when reacts with other solution to give products, the formula which is used to find the volume of either solution is given by:

${\text{M}}_{\text{1}}{\text{V}}_{\text{1}}{\text{=M}}_{\text{2}}{\text{V}}_{\text{2}}$

Where, M₁ and M₂ are molarity of the solution

V₁ and V₂ are volume of the solution