Explanation 1) Concept: We first find the rate of absorption and rate of emission in terms of photon flux. After taking the ratio of this two quantities, we can find the rate of emission in terms of rate of absorption. Substituting this value in the rate of emission formula, we can find the power of the emitter. 2) Formula: i) E p h = h c λ ii) R e m i t = P e m i t E p h 3) Given: i) Wavelength of sun light λ = 500 n m ii) Area A a b s = 2 × 10 - 6 m 2 iii) Distance of source from detector r = 3 m iv) Rate of absorption R a b s = 4 p h o t o n s / s 4) Calculations: The rate at which photons are absorbed by the detector is related to the rate of photon emission by the light source as follows:. Let I be the photon flux a distance r from the source. Since the photons are emitted uniformly in all directions, we have R e m i t = I A R e m i t = 4 π r 2 I … … … … … … … … … … … … … … … … … … … … … … … … … . 1 ) The detector absorbs the 80 % of flux. R a b s = 0.80 I A a b s … … … … … … … … … … … … … … … … … … … … … … … … … … 2 ) Taking the ratio of 1) and 2) and solving for R e m i t , we get, R a b s = 0.80 A a b s 4 π r 2 R e m i t R e m i t = 4 π r 2 0

Fundamentals Of Physics 11th Edition Loose-leaf Print Companion Volume 2 With Wileyplus Card Set

11th Edition

ISBN: 9781119463252

Author: David Halliday

Publisher: John Wiley and Sons

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Chapter 38, Problem 7P

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The power with which the emitter emits light.

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Chapter 38, Problem 6P

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A light detector (your eye) has an area of 2.00*10-6 m2 and absorbs 80% of the incident light, which is at wavelength 500 nm. The detector faces an isotropic source, 3.00 m from the source. If the detector absorbs photons at the rate of exactly 4.000 s-1, at what power does the emitter emit light?

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Chapter 38 Solutions

Fundamentals Of Physics 11th Edition Loose-leaf Print Companion Volume 2 With Wileyplus Card Set

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The power with which the emitter emits light.

Solution Summary: The author explains how the power of the emitter is 1.1times 10-10W.

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Chapter 38 Solutions

To find:

The power with which the emitter emits light.