Explanation 1) Concept: We find the total energy of the electron and the wave number in region 1. Finding the value of b and substituting in transmission coeffient formula, we can find the transmission coefficient of the barrier. Taking the product of transmission coefficient and the initial current of region 1, we can find the transmitted current in region 2. 2) Formula: i) E = 1 2 m v 2 ii) k = 2 π λ iii) T = e - 2 b L iv) b = 8 π 2 m U b - E h 2 v) T = I t I 0 3) Given: i) Speed of electrons v = 1.200 × 10 3 m s ii) Current I 0 = 9.000 m A iii) Height of potential barrier U b = - 4.719 μ V iv) Thickness L = 200.0 n m 4) Calculations: The energy of the electron in the region 1 is E = K + P . E E = 1 2 m v 2 + 0 E = 1 2 ( 9.11 × 10 - 31 k g ) 1.2 × 10 3 m s 2 E = 6.56 × 10 - 25 J E = 4.0995 μ e V The wave number in region 1 is k = 2 π λ The de-Broglie wavelength is λ = h p k = 2 π p h The linear momentum p = m v k = 2 π m v h k = 2 π ( 9.11 × 10 - 31 k g ) ( 1200 m s ) 6

Fundamentals Of Physics 11th Edition Loose-leaf Print Companion Volume 2 With Wileyplus Card Set

11th Edition

ISBN: 9781119463252

Author: David Halliday

Publisher: John Wiley and Sons

See similar textbooks

Concept explainers

Atomic Spectra

According to the Bohr model of an atom, the electron in an atom moves around a nucleus in fixed orbits with specific energies known as energy levels. The orbital energies are quantized. The electrons remain in these energy levels until they emit or absor…

Ruby Lasers

Lasers are devices that emit light using atoms or molecules at a certain wavelength and amplify the light to produce a narrow beam of radiation. It works as per the principle of electromagnetic radiation. Their source of emission contains the same freque…

Balmer Series

The spectrum of frequency observed when electromagnetic radiation is emitted from an atom when it goes from higher energy state to lower state, is known as emission spectrum. This transition occurs when an excited electron moves from higher to lower stat…

Emission Spectrum

Every state of matter tries to be at minimum potential energy or it can be said that the atoms of element/ substance arrange themselves such that overall energy is minimum.

Question

Chapter 38, Problem 78P

To determine

To find:

Transmitted current.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 38, Problem 77P

Chapter 38, Problem 79P

Students have asked these similar questions

A stream of electrons with a linear number density of 3.10 x 1011 electrons/meter are accelerated from rest by a 62.0-V potential difference applied across two parallel plates. The electrons then pass through an aperture in the high voltage plate and into a current collector where the beam current is measured. Note: The mass of an electron is 9.11 x 10-31 kg. (a) What is the magnitude of the electric field between the plates if they are 2.07 m apart? V/m (b) What is the final velocity of each electron? m/s (c) What is the beam current? A

The current of a beam of electrons, each with a speed of 900 m/s, is 5.00 mA. At one point along its path, the beam encounters a potential step of height -1.25 mV.What is the current on the other side of the step boundary?

A 52@mC charged particle moves parallel to a long wire with a speed of 720 m>s. The separation between the particle andthe wire is 13 cm, and the magnitude of the force exerted on the particle is 1.4 * 10-7N. Find (a) the magnitude of themagnetic field at the location of the particle and (b) the current in the wire.

Chapter 38 Solutions

Fundamentals Of Physics 11th Edition Loose-leaf Print Companion Volume 2 With Wileyplus Card Set

Ch. 38 - Prob. 1Q Ch. 38 - Prob. 2Q Ch. 38 - Prob. 3Q Ch. 38 - Prob. 4Q Ch. 38 - Prob. 5Q Ch. 38 - Prob. 6Q Ch. 38 - Prob. 7Q Ch. 38 - Prob. 8Q Ch. 38 - Prob. 9Q Ch. 38 - Prob. 10Q

Ch. 38 - Prob. 11Q Ch. 38 - Prob. 12Q Ch. 38 - Prob. 13Q Ch. 38 - Prob. 14Q Ch. 38 - Prob. 15Q Ch. 38 - Prob. 16Q Ch. 38 - Prob. 1P Ch. 38 - Prob. 2P Ch. 38 - Prob. 3P Ch. 38 - Prob. 4P Ch. 38 - Prob. 5P Ch. 38 - Prob. 6P Ch. 38 - Prob. 7P Ch. 38 - Prob. 8P Ch. 38 - Prob. 9P Ch. 38 - Prob. 10P Ch. 38 - Prob. 11P Ch. 38 - Prob. 12P Ch. 38 - Prob. 13P Ch. 38 - Prob. 14P Ch. 38 - Prob. 15P Ch. 38 - Prob. 16P Ch. 38 - Prob. 17P Ch. 38 - Prob. 18P Ch. 38 - Prob. 19P Ch. 38 - Prob. 20P Ch. 38 - Prob. 21P Ch. 38 - Prob. 22P Ch. 38 - Prob. 23P Ch. 38 - Prob. 24P Ch. 38 - Prob. 25P Ch. 38 - Prob. 26P Ch. 38 - Prob. 27P Ch. 38 - Prob. 28P Ch. 38 - Prob. 29P Ch. 38 - Prob. 30P Ch. 38 - Prob. 31P Ch. 38 - Prob. 32P Ch. 38 - Prob. 33P Ch. 38 - Prob. 34P Ch. 38 - Prob. 35P Ch. 38 - Prob. 36P Ch. 38 - Prob. 37P Ch. 38 - Prob. 38P Ch. 38 - Prob. 39P Ch. 38 - Prob. 40P Ch. 38 - Prob. 41P Ch. 38 - Prob. 42P Ch. 38 - Prob. 43P Ch. 38 - Prob. 44P Ch. 38 - Prob. 45P Ch. 38 - Prob. 46P Ch. 38 - Prob. 47P Ch. 38 - Prob. 48P Ch. 38 - Prob. 49P Ch. 38 - Prob. 50P Ch. 38 - Prob. 51P Ch. 38 - Prob. 52P Ch. 38 - Prob. 53P Ch. 38 - Prob. 54P Ch. 38 - Prob. 55P Ch. 38 - Prob. 56P Ch. 38 - Prob. 57P Ch. 38 - Prob. 58P Ch. 38 - Prob. 59P Ch. 38 - Prob. 60P Ch. 38 - Prob. 61P Ch. 38 - Prob. 62P Ch. 38 - Prob. 63P Ch. 38 - Prob. 64P Ch. 38 - Prob. 65P Ch. 38 - Prob. 66P Ch. 38 - Prob. 67P Ch. 38 - Prob. 68P Ch. 38 - Prob. 69P Ch. 38 - Prob. 70P Ch. 38 - Prob. 71P Ch. 38 - Prob. 72P Ch. 38 - Prob. 73P Ch. 38 - Prob. 74P Ch. 38 - Prob. 75P Ch. 38 - Prob. 76P Ch. 38 - Prob. 77P Ch. 38 - Prob. 78P Ch. 38 - Prob. 79P Ch. 38 - Prob. 80P Ch. 38 - Prob. 81P Ch. 38 - Prob. 82P Ch. 38 - Prob. 83P Ch. 38 - Prob. 84P Ch. 38 - Prob. 85P Ch. 38 - Prob. 86P Ch. 38 - Prob. 87P Ch. 38 - Prob. 88P Ch. 38 - Prob. 89P Ch. 38 - Prob. 90P

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Transmitted current.

Solution Summary: The author calculates the energy of the electron in the region 1 and the wave number in region 1.

Concept explainers

To find: Transmitted current.

Want to see the full answer?

Chapter 38 Solutions

To find:

Transmitted current.