Accelerating voltage required for the electrons to have the same resolving power as could be obtained using 100 k e V gamma rays.

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Answer 1

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Chapter 38, Problem 48P

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Accelerating voltage required for the electrons to have the same resolving power as could be obtained using 100 keV gamma rays.

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The smallest dimension (resolving power) that can be resolved by an electron microscope is equal to the de Broglie wavelength of its electrons.What accelerating voltage would be required for the electrons to have the same resolving power as could be obtained using 100 keV gamma rays?

The de Broglie wavelength of an electron has to do with spatial resolution of an electron microscope, which is often expressed in the unit of length Å (Angstrom). The 1 V potential difference causes an electron to gain kinetic energy EK of 1 electron Volt (eV). In the SI units, kinetic energy in eV must be converted to Joules. The conversion factor is 1 eV = 1.6 x 10-19 Joule. And, the formula for the wavelength is: λ = h / p = h / √(2 m EK) where m is electron mass. Calculate the de Broglie wavelength of an electron (in Å) when the electron is accelerated from rest through a potential difference of: a) 1 kV = 1,000 V (a low resolution setting of microscope), b) 10 kV = 10,000 V (intermediate resolution). c) 100 kV = 100,000 V (high resolution),

The diameter of the nucleus is about 12.1fm. What is the kinetic energy of a proton with a de Broglie wavelength of 12.1fm?

Answer 2

Question

Chapter 38, Problem 48P

To determine

To find:

Accelerating voltage required for the electrons to have the same resolving power as could be obtained using 100 keV gamma rays.

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Answer 3

Question

Chapter 38, Problem 48P

To determine

To find:

Accelerating voltage required for the electrons to have the same resolving power as could be obtained using 100 keV gamma rays.

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Answer 4

Question

Chapter 38, Problem 48P

To determine

To find:

Accelerating voltage required for the electrons to have the same resolving power as could be obtained using 100 keV gamma rays.

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Answer 5

Chapter 38, Problem 48P

To determine

To find:

Accelerating voltage required for the electrons to have the same resolving power as could be obtained using 100 keV gamma rays.

Answer 6

Chapter 38, Problem 48P

To determine

To find:

Accelerating voltage required for the electrons to have the same resolving power as could be obtained using 100 keV gamma rays.

Answer 7

Chapter 38, Problem 48P

To determine

To find:

Accelerating voltage required for the electrons to have the same resolving power as could be obtained using 100 keV gamma rays.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 38 - Prob. 1Q Ch. 38 - Prob. 2Q Ch. 38 - Prob. 3Q Ch. 38 - Prob. 4Q Ch. 38 - Prob. 5Q Ch. 38 - Prob. 6Q Ch. 38 - Prob. 7Q Ch. 38 - Prob. 8Q Ch. 38 - Prob. 9Q Ch. 38 - Prob. 10Q

Accelerating voltage required for the electrons to have the same resolving power as could be obtained using 100 k e V gamma rays.

Solution Summary: The author explains the concept of de Broglie wavelength and its formula, to find the wavelength.

Concept explainers

To find:

Accelerating voltage required for the electrons to have the same resolving power as could be obtained using 100 keV gamma rays.

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Chapter 38 Solutions

Accelerating voltage required for the electrons to have the same resolving power as could be obtained using 100 k e V gamma rays.

Solution Summary: The author explains the concept of de Broglie wavelength and its formula, to find the wavelength.

Concept explainers

To find: Accelerating voltage required for the electrons to have the same resolving power as could be obtained using 100 keV gamma rays.

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Chapter 38 Solutions

To find:

Accelerating voltage required for the electrons to have the same resolving power as could be obtained using 100 keV gamma rays.