Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
2nd Edition
ISBN: 9780076602919
Author: McGraw-Hill Education
Publisher: McGraw-Hill Education
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Concept explainers

Transformation of Graphs
The word ‘transformation’ means modification. Transformation of the graph of a function is a process by which we modify or change the original graph and make a new graph.
Exponential Functions
The exponential function is a type of mathematical function which is used in real-world contexts. It helps to find out the exponential decay model or exponential growth model, in mathematical models. In this topic, we will understand descriptive rules, c…
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Question
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Chapter 3.8, Problem 66PFA

(a)

To determine

The graph of the function.

(a)

Expert Solution
Check Mark

Answer to Problem 66PFA

Therefore, graph of the function is represented as,

  Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1), Chapter 3.8, Problem 66PFA , additional homework tip 1

Explanation of Solution

Given information: The equation in terms of x is given as,

  g(x)=15|x−20|+2

The general form is given as,

  f(x)=a|x−h|+kOn compairing with general form,a=15,h=20,k=2

Therefore, graph of the function is represented as,

  Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1), Chapter 3.8, Problem 66PFA , additional homework tip 2

(b)

To determine

The vertex of the function.

(b)

Expert Solution
Check Mark

Answer to Problem 66PFA

Therefore, the vertex of the function is (20,2) it is represented as by (h,k).

Explanation of Solution

Given information: The equation in terms of x is given as,

  g(x)=15|x−20|+2

The vertex for the function’s graph is given as by comparing it with general form,

  f(x)=a|x−h|+kOn compairing with general form,a=15,h=20,k=2

  Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1), Chapter 3.8, Problem 66PFA , additional homework tip 3

The vertex of the function is (20,2) it is represented as by (h,k).

(c)

To determine

The distance between ship and lighthouse when spotted by captain.

(c)

Expert Solution
Check Mark

Answer to Problem 66PFA

Therefore, distance between ship and lighthouse is 6 units.

Explanation of Solution

Given information: The equation in terms of x is given as,

  g(x)=15|x−20|+2

The distance from ship to lighthouse when the captain first spots it,

  Putting x=0 we get,g(0)=15|0−20|+2g(0)=6.

So, therefore distance between ship and lighthouse is 6 units.

(d)

To determine

The graph g(x) as a transformation of the graph of f(x)=|x|.

(d)

Expert Solution
Check Mark

Answer to Problem 66PFA

Thereforetransformation of g(x) as f(x) is ,

  Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1), Chapter 3.8, Problem 66PFA , additional homework tip 4

Explanation of Solution

Given information: The equation in terms of x is given as,

  g(x)=15|x−20|+2

The graph g(x)=15|x−20|+2 as a transformation of the graph of f(x)=|x| is represented as,

  Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1), Chapter 3.8, Problem 66PFA , additional homework tip 5

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Chapter 3.8, Problem 65PFA
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Chapter 3, Problem 1MCQ

Chapter 3 Solutions

Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)

Ch. 3.1 - Prob. 1AGPCh. 3.1 - Prob. 1BGPCh. 3.1 - Prob. 2GPCh. 3.1 - Prob. 3GPCh. 3.1 - Prob. 4AGPCh. 3.1 - Prob. 4BGPCh. 3.1 - Prob. 5AGPCh. 3.1 - Prob. 5BGPCh. 3.1 - Prob. 5CGPCh. 3.1 - Prob. 1CYU
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Prob. 13MCQCh. 3 - Prob. 14MCQCh. 3 - Prob. 15MCQCh. 3 - Prob. 16MCQCh. 3 - Prob. 17MCQCh. 3 - Prob. 18MCQCh. 3 - Prob. 19MCQCh. 3 - Prob. 20MCQCh. 3 - Prob. 21MCQCh. 3 - Prob. 22MCQCh. 3 - Prob. 23MCQCh. 3 - Prob. 24MCQCh. 3 - Prob. 25MCQCh. 3 - Prob. 26MCQCh. 3 - Prob. 1SGRCh. 3 - Prob. 2SGRCh. 3 - Prob. 3SGRCh. 3 - Prob. 4SGRCh. 3 - Prob. 5SGRCh. 3 - Prob. 6SGRCh. 3 - Prob. 7SGRCh. 3 - Prob. 8SGRCh. 3 - Prob. 9SGRCh. 3 - Prob. 10SGRCh. 3 - Prob. 11SGRCh. 3 - Prob. 12SGRCh. 3 - Prob. 13SGRCh. 3 - Prob. 14SGRCh. 3 - Prob. 15SGRCh. 3 - Prob. 16SGRCh. 3 - Prob. 17SGRCh. 3 - Prob. 18SGRCh. 3 - Prob. 19SGRCh. 3 - Prob. 20SGRCh. 3 - Prob. 21SGRCh. 3 - Prob. 22SGRCh. 3 - Prob. 23SGRCh. 3 - Prob. 24SGRCh. 3 - Prob. 25SGRCh. 3 - Prob. 26SGRCh. 3 - Prob. 27SGRCh. 3 - Prob. 28SGRCh. 3 - Prob. 29SGRCh. 3 - Prob. 30SGRCh. 3 - Prob. 31SGRCh. 3 - Prob. 32SGRCh. 3 - Prob. 33SGRCh. 3 - Prob. 34SGRCh. 3 - Prob. 35SGRCh. 3 - Prob. 36SGRCh. 3 - Prob. 37SGRCh. 3 - Prob. 38SGRCh. 3 - Prob. 39SGRCh. 3 - Prob. 40SGRCh. 3 - Prob. 41SGRCh. 3 - Prob. 42SGRCh. 3 - Prob. 43SGRCh. 3 - Prob. 44SGRCh. 3 - Prob. 45SGRCh. 3 - Prob. 46SGRCh. 3 - Prob. 47SGRCh. 3 - Prob. 48SGRCh. 3 - Prob. 49SGRCh. 3 - Prob. 50SGRCh. 3 - Prob. 51SGRCh. 3 - Prob. 52SGRCh. 3 - Prob. 53SGRCh. 3 - Prob. 54SGRCh. 3 - Prob. 55SGRCh. 3 - Prob. 56SGRCh. 3 - Prob. 57SGRCh. 3 - Prob. 58SGRCh. 3 - Prob. 59SGRCh. 3 - Prob. 60SGRCh. 3 - Prob. 61SGRCh. 3 - Prob. 62SGRCh. 3 - Prob. 63SGRCh. 3 - Prob. 64SGRCh. 3 - Prob. 65SGRCh. 3 - Prob. 66SGRCh. 3 - Prob. 67SGRCh. 3 - Prob. 68SGRCh. 3 - Prob. 69SGRCh. 3 - Prob. 70SGRCh. 3 - Prob. 71SGRCh. 3 - Prob. 72SGRCh. 3 - Prob. 73SGRCh. 3 - Prob. 74SGRCh. 3 - Prob. 75SGRCh. 3 - Prob. 76SGRCh. 3 - Prob. 77SGRCh. 3 - Prob. 78SGRCh. 3 - Prob. 1PTCh. 3 - Prob. 2PTCh. 3 - Prob. 3PTCh. 3 - Prob. 4PTCh. 3 - Prob. 5PTCh. 3 - Prob. 6PTCh. 3 - Prob. 7PTCh. 3 - Prob. 8PTCh. 3 - Prob. 9PTCh. 3 - Prob. 10PTCh. 3 - Prob. 11PTCh. 3 - Prob. 12PTCh. 3 - Prob. 13PTCh. 3 - Prob. 14PTCh. 3 - Prob. 15PTCh. 3 - Prob. 16PTCh. 3 - Prob. 17PTCh. 3 - Prob. 18PTCh. 3 - Prob. 19PTCh. 3 - Prob. 20PTCh. 3 - Prob. 21PTCh. 3 - Prob. 22PTCh. 3 - Prob. 23PTCh. 3 - Prob. 24PTCh. 3 - Prob. 25PTCh. 3 - Prob. 26PTCh. 3 - Prob. 27PTCh. 3 - Prob. 1CRCh. 3 - Prob. 2CRCh. 3 - Prob. 3CRCh. 3 - Prob. 4CRCh. 3 - Prob. 5CRCh. 3 - Prob. 6CRCh. 3 - Prob. 7CRCh. 3 - Prob. 8CRCh. 3 - Prob. 9CRCh. 3 - Prob. 10CRCh. 3 - Prob. 11CRCh. 3 - Prob. 12CRCh. 3 - Prob. 13CRCh. 3 - Prob. 14CR

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