Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
2nd Edition
ISBN: 9780076602919
Author: McGraw-Hill Education
Publisher: McGraw-Hill Education
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Concept explainers

Sequence and Series
A sequence is defined as a collection of things. Series is defined to sum the things one by one in the sequence. It was invented by German mathematician Carl Friedrich Gauss.
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Chapter 3, Problem 13CR

a.

To determine

To find: equation of height of balloon related to time and position of balloon after 1,2,3,4 minutes under given condition.

a.

Expert Solution
Check Mark

Answer to Problem 13CR

When t =1, then, h =75 feet

t =2, then, h =90 feet

t =3, then, h =104 feet

t =4, then, h =120 feet

Explanation of Solution

Given information: A balloon started ascending when it is at the height of 60 feet and its height increases by 15 feet after every minute.

Since a balloon started ascending when it is at the height of 60 feet and its height increases by 15 feet after every minute.

Then its equation is given by,

  h=60+15t , where h is in feet and t is in minute

In order to find position of balloon at t=1, 2, 3, 4 minute we have to put these values in above equation

When t =1, then, h =75 feet

t =2, then, h =90 feet

t =3, then, h =104 feet

t =4, then, h =120 feet

b.

To determine

To write: an algebraicequation for the sequence that can be used to find height, h, of the balloon after t minutes.

b.

Expert Solution
Check Mark

Answer to Problem 13CR

  h=60+15t

Explanation of Solution

Given information: A balloon started ascending when it is at the height of 60 feet and its height increases by 15 feet after every minute.

The equation that best describe the above given information is h=60+15t

c.

To determine

To find: the height of the hot air balloon after climbing for 8 minutes.

c.

Expert Solution
Check Mark

Answer to Problem 13CR

180 feet

Explanation of Solution

Given information: an equation is given as follows- . h=60+15t

In order to find the height of balloon after climbing for 8 minutes.

Put t=8 in above given equation,

  h=60+15t⇒h=60+15×8⇒h=60+120=180

d.

To determine

To write: which mathematical practice have I used to solve above problem.

d.

Expert Solution
Check Mark

Explanation of Solution

Given information: A balloon started ascending when it is at the height of 60 feet and its height increases by 15 feet after every minute.

In order to solve above problem we have used height as a function of time and write a linear equation according to the given information.

  1. The required equation is, h =60+ 15t
  2. Putting t =8 in the above equation we get, h=60+120=180 feet.
  3. In order to solve above problem we have used height as a function of time.
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Chapter 3, Problem 12CR
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Chapter 3, Problem 14CR

Chapter 3 Solutions

Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)

Ch. 3.1 - Prob. 1AGPCh. 3.1 - Prob. 1BGPCh. 3.1 - Prob. 2GPCh. 3.1 - Prob. 3GPCh. 3.1 - Prob. 4AGPCh. 3.1 - Prob. 4BGPCh. 3.1 - Prob. 5AGPCh. 3.1 - Prob. 5BGPCh. 3.1 - Prob. 5CGPCh. 3.1 - Prob. 1CYU
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Prob. 3CYUCh. 3.5 - Prob. 4CYUCh. 3.5 - Prob. 5CYUCh. 3.5 - Prob. 6CYUCh. 3.5 - Prob. 7CYUCh. 3.5 - Prob. 8CYUCh. 3.5 - Prob. 9CYUCh. 3.5 - Prob. 10CYUCh. 3.5 - Prob. 11CYUCh. 3.5 - Prob. 12PPSCh. 3.5 - Prob. 13PPSCh. 3.5 - Prob. 14PPSCh. 3.5 - Prob. 15PPSCh. 3.5 - Prob. 16PPSCh. 3.5 - Prob. 17PPSCh. 3.5 - Prob. 18PPSCh. 3.5 - Prob. 19PPSCh. 3.5 - Prob. 20PPSCh. 3.5 - Prob. 21PPSCh. 3.5 - Prob. 22PPSCh. 3.5 - Prob. 23PPSCh. 3.5 - Prob. 24PPSCh. 3.5 - Prob. 25PPSCh. 3.5 - Prob. 26PPSCh. 3.5 - Prob. 27PPSCh. 3.5 - Prob. 28PPSCh. 3.5 - Prob. 29PPSCh. 3.5 - Prob. 30PPSCh. 3.5 - Prob. 31PPSCh. 3.5 - Prob. 32PPSCh. 3.5 - Prob. 33PPSCh. 3.5 - Prob. 34PPSCh. 3.5 - Prob. 35PPSCh. 3.5 - Prob. 36PPSCh. 3.5 - Prob. 37PPSCh. 3.5 - Prob. 38PPSCh. 3.5 - Prob. 39PPSCh. 3.5 - Prob. 40PPSCh. 3.5 - Prob. 41PPSCh. 3.5 - Prob. 42PPSCh. 3.5 - Prob. 43PPSCh. 3.5 - Prob. 44PPSCh. 3.5 - Prob. 45PPSCh. 3.5 - Prob. 46PPSCh. 3.5 - Prob. 47PPSCh. 3.5 - Prob. 48PPSCh. 3.5 - Prob. 49PPSCh. 3.5 - Prob. 50PPSCh. 3.5 - 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Prob. 17PTCh. 3 - Prob. 18PTCh. 3 - Prob. 19PTCh. 3 - Prob. 20PTCh. 3 - Prob. 21PTCh. 3 - Prob. 22PTCh. 3 - Prob. 23PTCh. 3 - Prob. 24PTCh. 3 - Prob. 25PTCh. 3 - Prob. 26PTCh. 3 - Prob. 27PTCh. 3 - Prob. 1CRCh. 3 - Prob. 2CRCh. 3 - Prob. 3CRCh. 3 - Prob. 4CRCh. 3 - Prob. 5CRCh. 3 - Prob. 6CRCh. 3 - Prob. 7CRCh. 3 - Prob. 8CRCh. 3 - Prob. 9CRCh. 3 - Prob. 10CRCh. 3 - Prob. 11CRCh. 3 - Prob. 12CRCh. 3 - Prob. 13CRCh. 3 - Prob. 14CR

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