Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
2nd Edition
ISBN: 9780076602919
Author: McGraw-Hill Education
Publisher: McGraw-Hill Education
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Question
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Chapter 3.2, Problem 58PFA

a

To determine

To find: The correct option.

a

Expert Solution
Check Mark

Answer to Problem 58PFA

The answer is C: 15; the greatest number of sweatshirts that the class can buy.

Explanation of Solution

Given information: The function y=−1.5x+22.5 represents the possible numbers of sweatshirts x and T-shirts y the class could order for $180.

Calculation:

As per the given problem

  y=−1.5x+22.5 …… (1), where x represents the sweatshirts and y represents the T-shirts

The zero of the function means when y = 0

  0=−1.5x+22.51.5x=22.5−0x=15

So, when y = 0 then x = 15

And from the equation as the value of y increases the value of x decreases

Therefore y = 0 , x = 15 represents the maximum number of sweatshirts( x ) they can order for $180

Hence the answer is = C: 15; the greatest number of sweatshirts that the class can buy.

b

To determine

To calculate: The domain of the function in the context of the situation.

b

Expert Solution
Check Mark

Answer to Problem 58PFA

The domain of the function is D= {0, 15}, which represents the number of sweatshirts the class can buy.

Explanation of Solution

Given information: The function y=−1.5x+22.5 represents the possible numbers of sweatshirts x and T-shirts y the class could order for $180.

Calculation: The Domain of the function is the range of x i.e. the minimum and maximum value of x.

Now since x represents number of sweatshirts so it can’t be less than 0, so xmin = 0

And we already know xmax = 15 from above

Hence the range of x is {0, 15}.

c.

To determine

To calculate: The range of the function in the context of the situation.

c.

Expert Solution
Check Mark

Answer to Problem 58PFA

The Range of the function is R= {0, 22}, which represents the number of T-shirts the class can buy.

Explanation of Solution

Given information: The function y=−1.5x+22.5 represents the possible numbers of sweatshirts x and T-shirts y the class could order for $180.

Calculation: The range of the function is the range of y i.e. the minimum and maximum value of y

Now since y represents number of sweatshirts so it can’t be less than 0, so ymin = 0

For y to be maximum x will be minimum i.e. = 0

So put x = 0 in the above equation, we get,

  y=−15×0+22.5y=22.5

Since y is an integer, so ymax= 22

Hence the range of y is {0, 22}.

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Chapter 3.2, Problem 57PFA
Next
Chapter 3.3, Problem 1AGP

Chapter 3 Solutions

Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)

Ch. 3.1 - Prob. 1AGPCh. 3.1 - Prob. 1BGPCh. 3.1 - Prob. 2GPCh. 3.1 - Prob. 3GPCh. 3.1 - Prob. 4AGPCh. 3.1 - Prob. 4BGPCh. 3.1 - Prob. 5AGPCh. 3.1 - Prob. 5BGPCh. 3.1 - Prob. 5CGPCh. 3.1 - Prob. 1CYU
Ch. 3.1 - Prob. 2CYUCh. 3.1 - Prob. 3CYUCh. 3.1 - Prob. 4CYUCh. 3.1 - Prob. 5CYUCh. 3.1 - Prob. 6CYUCh. 3.1 - Prob. 7CYUCh. 3.1 - Prob. 8CYUCh. 3.1 - Prob. 9CYUCh. 3.1 - Prob. 10CYUCh. 3.1 - Prob. 11CYUCh. 3.1 - Prob. 12CYUCh. 3.1 - Prob. 13PPSCh. 3.1 - Prob. 14PPSCh. 3.1 - Prob. 15PPSCh. 3.1 - Prob. 16PPSCh. 3.1 - Prob. 17PPSCh. 3.1 - Prob. 18PPSCh. 3.1 - Prob. 19PPSCh. 3.1 - Prob. 20PPSCh. 3.1 - Prob. 21PPSCh. 3.1 - Prob. 22PPSCh. 3.1 - Prob. 23PPSCh. 3.1 - Prob. 24PPSCh. 3.1 - Prob. 25PPSCh. 3.1 - Prob. 26PPSCh. 3.1 - Prob. 27PPSCh. 3.1 - Prob. 28PPSCh. 3.1 - Prob. 29PPSCh. 3.1 - Prob. 30PPSCh. 3.1 - Prob. 31PPSCh. 3.1 - Prob. 32PPSCh. 3.1 - Prob. 33PPSCh. 3.1 - Prob. 34PPSCh. 3.1 - Prob. 35PPSCh. 3.1 - Prob. 36PPSCh. 3.1 - Prob. 37PPSCh. 3.1 - Prob. 38PPSCh. 3.1 - Prob. 39PPSCh. 3.1 - Prob. 40PPSCh. 3.1 - Prob. 41PPSCh. 3.1 - Prob. 42PPSCh. 3.1 - Prob. 43PPSCh. 3.1 - Prob. 44PPSCh. 3.1 - Prob. 45PPSCh. 3.1 - Prob. 46PPSCh. 3.1 - Prob. 47PPSCh. 3.1 - Prob. 48PPSCh. 3.1 - Prob. 49PPSCh. 3.1 - 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Prob. 3CYUCh. 3.5 - Prob. 4CYUCh. 3.5 - Prob. 5CYUCh. 3.5 - Prob. 6CYUCh. 3.5 - Prob. 7CYUCh. 3.5 - Prob. 8CYUCh. 3.5 - Prob. 9CYUCh. 3.5 - Prob. 10CYUCh. 3.5 - Prob. 11CYUCh. 3.5 - Prob. 12PPSCh. 3.5 - Prob. 13PPSCh. 3.5 - Prob. 14PPSCh. 3.5 - Prob. 15PPSCh. 3.5 - Prob. 16PPSCh. 3.5 - Prob. 17PPSCh. 3.5 - Prob. 18PPSCh. 3.5 - Prob. 19PPSCh. 3.5 - Prob. 20PPSCh. 3.5 - Prob. 21PPSCh. 3.5 - Prob. 22PPSCh. 3.5 - Prob. 23PPSCh. 3.5 - Prob. 24PPSCh. 3.5 - Prob. 25PPSCh. 3.5 - Prob. 26PPSCh. 3.5 - Prob. 27PPSCh. 3.5 - Prob. 28PPSCh. 3.5 - Prob. 29PPSCh. 3.5 - Prob. 30PPSCh. 3.5 - Prob. 31PPSCh. 3.5 - Prob. 32PPSCh. 3.5 - Prob. 33PPSCh. 3.5 - Prob. 34PPSCh. 3.5 - Prob. 35PPSCh. 3.5 - Prob. 36PPSCh. 3.5 - Prob. 37PPSCh. 3.5 - Prob. 38PPSCh. 3.5 - Prob. 39PPSCh. 3.5 - Prob. 40PPSCh. 3.5 - Prob. 41PPSCh. 3.5 - Prob. 42PPSCh. 3.5 - Prob. 43PPSCh. 3.5 - Prob. 44PPSCh. 3.5 - Prob. 45PPSCh. 3.5 - Prob. 46PPSCh. 3.5 - Prob. 47PPSCh. 3.5 - Prob. 48PPSCh. 3.5 - Prob. 49PPSCh. 3.5 - Prob. 50PPSCh. 3.5 - Prob. 51PPSCh. 3.5 - Prob. 52HPCh. 3.5 - Prob. 53HPCh. 3.5 - Prob. 54HPCh. 3.5 - Prob. 55HPCh. 3.5 - Prob. 56HPCh. 3.5 - Prob. 57PFACh. 3.5 - Prob. 58PFACh. 3.5 - Prob. 59PFACh. 3.5 - Prob. 60PFACh. 3.5 - Prob. 61PFACh. 3.5 - Prob. 62PFACh. 3.5 - Prob. 63PFACh. 3.5 - Prob. 64PFACh. 3.6 - Prob. 1AGPCh. 3.6 - Prob. 1BGPCh. 3.6 - Prob. 2GPCh. 3.6 - Prob. 3AGPCh. 3.6 - Prob. 3BGPCh. 3.6 - Prob. 3CGPCh. 3.6 - Prob. 3DGPCh. 3.6 - Prob. 4GPCh. 3.6 - Prob. 1CYUCh. 3.6 - Prob. 2CYUCh. 3.6 - Prob. 3CYUCh. 3.6 - Prob. 4CYUCh. 3.6 - Prob. 5CYUCh. 3.6 - Prob. 6CYUCh. 3.6 - Prob. 7CYUCh. 3.6 - Prob. 8PPSCh. 3.6 - Prob. 9PPSCh. 3.6 - Prob. 10PPSCh. 3.6 - Prob. 11PPSCh. 3.6 - Prob. 12PPSCh. 3.6 - Prob. 13PPSCh. 3.6 - Prob. 14PPSCh. 3.6 - Prob. 15PPSCh. 3.6 - Prob. 16PPSCh. 3.6 - Prob. 17PPSCh. 3.6 - Prob. 18PPSCh. 3.6 - Prob. 19PPSCh. 3.6 - Prob. 20PPSCh. 3.6 - Prob. 21PPSCh. 3.6 - Prob. 22PPSCh. 3.6 - Prob. 23PPSCh. 3.6 - Prob. 24PPSCh. 3.6 - Prob. 25PPSCh. 3.6 - Prob. 26PPSCh. 3.6 - Prob. 27PPSCh. 3.6 - Prob. 28PPSCh. 3.6 - Prob. 29PPSCh. 3.6 - Prob. 30PPSCh. 3.6 - Prob. 31PPSCh. 3.6 - Prob. 32HPCh. 3.6 - Prob. 33HPCh. 3.6 - Prob. 34HPCh. 3.6 - Prob. 35HPCh. 3.6 - Prob. 36HPCh. 3.6 - Prob. 37PFACh. 3.6 - Prob. 38PFACh. 3.6 - Prob. 39PFACh. 3.6 - Prob. 40PFACh. 3.6 - Prob. 41PFACh. 3.6 - Prob. 42PFACh. 3.6 - Prob. 43PFACh. 3.7 - Prob. 1GPCh. 3.7 - Prob. 2GPCh. 3.7 - Prob. 3GPCh. 3.7 - Prob. 4GPCh. 3.7 - Prob. 1CYUCh. 3.7 - Prob. 2CYUCh. 3.7 - Prob. 3CYUCh. 3.7 - Prob. 4CYUCh. 3.7 - Prob. 5CYUCh. 3.7 - Prob. 6CYUCh. 3.7 - Prob. 7CYUCh. 3.7 - Prob. 8PPSCh. 3.7 - Prob. 9PPSCh. 3.7 - Prob. 10PPSCh. 3.7 - Prob. 11PPSCh. 3.7 - Prob. 12PPSCh. 3.7 - Prob. 13PPSCh. 3.7 - Prob. 14PPSCh. 3.7 - Prob. 15PPSCh. 3.7 - Prob. 16PPSCh. 3.7 - Prob. 17PPSCh. 3.7 - Prob. 18PPSCh. 3.7 - Prob. 19PPSCh. 3.7 - Prob. 20PPSCh. 3.7 - Prob. 21PPSCh. 3.7 - Prob. 22PPSCh. 3.7 - Prob. 23PPSCh. 3.7 - Prob. 24PPSCh. 3.7 - Prob. 25PPSCh. 3.7 - Prob. 26PPSCh. 3.7 - Prob. 27PPSCh. 3.7 - Prob. 28PPSCh. 3.7 - Prob. 29PPSCh. 3.7 - 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