Chapter 3.6, Problem 55STP

To determine

Tofind the fraction of families that grill out 2 or more times per month.

Answer to Problem 55STP

The fraction of families that grill out 2 or more times per month is obtained as $\frac{7}{10}$ and the option H is the correct answer.

Explanation of Solution

Given information :

The table for families that grill out per month is given as,

Times per month	Fraction of people
Less than 1	$\frac{11}{50}$
1	$\frac{2}{25}$
2-3	$\frac{4}{25}$
4 or more	$\frac{27}{50}$

There are 4 different options given as,

F. $\frac{2}{25}$

G. $\frac{23}{100}$

H. $\frac{7}{10}$

J. $\frac{39}{50}$

Calculation :

The fraction of families that grill out 2 or more times per monthcan be obtained as,

  $\begin{array}{l}\frac{4}{25}+\frac{27}{50}\\ =\frac{4}{25}\cdot \frac{2}{2}+\frac{27}{50}\left[\text{use 50 as the common denominator}\right]\\ =\frac{8}{50}+\frac{27}{50}\left[\text{write the fraction using common denominator}\right]\\ =\frac{35}{50}\left[\text{add the numerator}\right]\\ =\frac{7}{10}\left[\text{simplify}\right]\end{array}$

Therefore,

The fraction of families that grill out 2 or more times per month is obtained as $\frac{7}{10}$ and the option H is the correct answer.