Chapter 3.1, Problem 67STP

To determine

To choose : the correct pair of fraction.

Answer to Problem 67STP

The correct answer isC$\frac{7}{10}\text{ and }\frac{3}{4}$ .

Explanation of Solution

Given information :

The fraction is $\frac{7}{9}$ .

Convert the fraction in decimal form

  $\frac{7}{9}=0.\overline{7}$

Now, convert the pair of option Ain decimal form

  $\begin{array}{l}\frac{3}{5}=0.6\\ \frac{3}{4}=0.75\end{array}$

So, $0.\overline{7}$ is not found between $\frac{3}{5}\text{ and }\frac{3}{4}$

Now, convert the pair of option Bin decimal form

  $\begin{array}{l}\frac{7}{10}=0.7\\ \frac{3}{4}=0.75\end{array}$

So, $0.\overline{7}$ is not found between $\frac{7}{10}\text{ and }\frac{3}{4}$

Now, convert the pair of option Cin decimal form

  $\begin{array}{l}\frac{7}{10}=0.7\\ \frac{4}{5}=0.8\end{array}$

So, $0.\overline{7}$ is found between $\frac{7}{10}\text{ and }\frac{4}{5}$

Now, convert the pair of option Din decimal form

  $\begin{array}{l}\frac{3}{5}=0.6\\ \frac{2}{3}=0.\overline{6}\end{array}$

So, $0.\overline{7}$ is not found between $\frac{3}{5}\text{ and }\frac{2}{3}$ .

Hence, thecorrect answer is C$\frac{7}{10}\text{ and }\frac{3}{4}$ .