(a)
To find the number of students voted for Hector as per the given information.
(a)
Answer to Problem 50IP
The number of students voted for Hector are 324.
Explanation of Solution
Given information: Total number of students in the class are 540.
Fraction of students voted for Hector are
Total number of students voted for Hector are:
Hence, the number of students voted for Hector are 324.
(b)
To find the number of students voted for Nora as per the given information.
(b)
Answer to Problem 50IP
The number of students voted for Nora are 180.
Explanation of Solution
Given information: Total number of students in the class are 540.
Fraction of students voted for Nora are
Total number of students voted for Nora are:
Hence, the number of students voted for Nora are 180.
c.
To find the fraction of students voted for other candidates other than Hector and Nora.
c.
Answer to Problem 50IP
The fraction of candidates are
Explanation of Solution
Given information: Total number of students in the class are 540.
Total fraction of students voted for Hector and Nora are:
The remaining fraction of students are:
From this, it is concluded that there are more candidates for the class president and the fraction of students voted for them are
Chapter 3 Solutions
Glencoe Math Accelerated, Student Edition
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