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(a)
To find the number of students voted for Hector as per the given information.
(a)
![Check Mark](/static/check-mark.png)
Answer to Problem 50IP
The number of students voted for Hector are 324.
Explanation of Solution
Given information: Total number of students in the class are 540.
Fraction of students voted for Hector are
Total number of students voted for Hector are:
Hence, the number of students voted for Hector are 324.
(b)
To find the number of students voted for Nora as per the given information.
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 50IP
The number of students voted for Nora are 180.
Explanation of Solution
Given information: Total number of students in the class are 540.
Fraction of students voted for Nora are
Total number of students voted for Nora are:
Hence, the number of students voted for Nora are 180.
c.
To find the fraction of students voted for other candidates other than Hector and Nora.
c.
![Check Mark](/static/check-mark.png)
Answer to Problem 50IP
The fraction of candidates are
Explanation of Solution
Given information: Total number of students in the class are 540.
Total fraction of students voted for Hector and Nora are:
The remaining fraction of students are:
From this, it is concluded that there are more candidates for the class president and the fraction of students voted for them are
Chapter 3 Solutions
Glencoe Math Accelerated, Student Edition
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