Chapter 3.6, Problem 53STP

To determine

Tofind the total amount of snack mix.

Answer to Problem 53STP

The total amount of snack mix is obtained as $6\frac{7}{12}\text{ c}$ , and the option D is the correct answer.

Explanation of Solution

Given information :

The snack mix contains $2\frac{1}{3}$ cups of mixed nuts, $3\frac{1}{2}$ cups of granola, and $\frac{3}{4}$ cup of raisins.

There are 4 different options given as,

A. $5\frac{2}{3}\text{ c}$

B. $6\frac{2}{3}\text{ c}$

C. $5\frac{7}{12}\text{ c}$

D. $6\frac{7}{12}\text{ c}$

Calculation :

Thetotal amount of snack mixcan be obtained as,

  $\begin{array}{l}2\frac{1}{3}+3\frac{1}{2}+\frac{3}{4}\\ =\frac{7}{3}+\frac{7}{2}+\frac{3}{4}\\ =\frac{7}{3}\cdot \frac{4}{4}+\frac{7}{2}\cdot \frac{6}{6}+\frac{3}{4}\cdot \frac{3}{3}\left[\text{use 12 as the common denominator}\right]\\ =\frac{28}{12}+\frac{42}{12}\text{+}\frac{9}{12}\left[\text{write the fraction using common denominator}\right]\\ =\frac{79}{12}\left[\text{add the numerator}\right]\\ =6\frac{7}{12}\left[\text{simplify}\right]\end{array}$

Therefore,

The total amount of snack mixis obtained as $6\frac{7}{12}\text{ c}$ , and the option D is the correct answer.