Concept explainers
a.
To determine the regression feature of a graphing utility to find logistic model and power model for the data.
a.

Answer to Problem 36E
The logistic model is
Explanation of Solution
Given:
Consider the given information,
The data provided are
(1,11.21),(2,20.77),(3,28.94),(4,35.92),(5,41.87),(6,46.96),(7,55.01),(8,58.17),(10,60.87),(11,63.18),(12,65.15),(13,66.84),(14,68.27),(15,69.50)
Calculation:
Using the graphing utility, the logistic model
The power model
Conclusion:
Therefore, the logistic model is
b.
To determine which model fits the best to the data.
b.

Answer to Problem 36E
The logistic model fits the best for the model.
Explanation of Solution
Given:
Consider the given information,
The data provided are
(1,11.21),(2,20.77),(3,28.94),(4,35.92),(5,41.87),(6,46.96),(7,55.01),(8,58.17),(10,60.87),(11,63.18),(12,65.15),(13,66.84),(14,68.27),(15,69.50)
Graph:
Interpretation:
From the graph, it is clear that the logistic model fits the best for the given data.
c.
To determine the length of 17 years old yellowtail snapper by using part(a).
c.

Answer to Problem 36E
The length of the 17 years old yellowtail snapper is
Explanation of Solution
Given:
Consider the given information,
The data provided are
(1,11.21),(2,20.77),(3,28.94),(4,35.92),(5,41.87),(6,46.96),(7,55.01),(8,58.17),(10,60.87),(11,63.18),(12,65.15),(13,66.84),(14,68.27),(15,69.50)
Calculation:
From the given data,
Conclusion:
Therefore, the length of the 17 years old yellowtail snapper is
Chapter 3 Solutions
PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
- Question 4. Suppose you need to know an equation of the tangent plane to a surface S at the point P(2, 1, 3). You don't have an equation for S but you know that the curves r1(t) = (2 + 3t, 1 — t², 3 − 4t + t²) r2(u) = (1 + u², 2u³ − 1, 2u + 1) both lie on S. (a) Check that both r₁ and r2 pass through the point P. 1 (b) Give the expression of the 074 in two ways Ət ⚫ in terms of 32 and 33 using the chain rule მყ ⚫ in terms of t using the expression of z(t) in the curve r1 (c) Similarly, give the expression of the 22 in two ways Əz ди ⚫ in terms of oz and oz using the chain rule Əz მყ • in terms of u using the expression of z(u) in the curve r2 (d) Deduce the partial derivative 32 and 33 at the point P and the equation of მე მყ the tangent planearrow_forwardCoast Guard Patrol Search Mission The pilot of a Coast Guard patrol aircraft on a search mission had just spotted a disabled fishing trawler and decided to go in for a closer look. Flying in a straight line at a constant altitude of 1000 ft and at a steady speed of 256 ft/s, the aircraft passed directly over the trawler. How fast (in ft/s) was the aircraft receding from the trawler when it was 1400 ft from the trawler? (Round your answer to one decimal places.) 1000 ft 180 × ft/s Need Help? Read It SUBMIT ANSWERarrow_forward6. The largest interval in which the solution of (cos t)y′′ +t^2y′ − (5/t)y = e^t/(t−3) , y(1) = 2, y′(1) = 0is guaranteed to exist by the Existence and Uniqueness Theorem is:A. (0, ∞) B. (π/2, 3) C. (0,π/2) D. (0, π) E. (0, 3)arrow_forward
- 12. For the differential equation in the previous question, what is the correct form for a particularsolution?A. yp = Ae^t + Bt^2 B. yp = Ae^t + Bt^2 + Ct + DC. yp = Ate^t + Bt^2 D. yp = Ate^t + Bt^2 + Ct + D Previous differential equation y′′ − 4y′ + 3y = e^t + t^2arrow_forward16. The appropriate form for the particular solution yp(x) of y^(3) − y′′ − 2y′ = x^2 + e^2x isA. yp(x) = Ax^2 + Bx + C + De^2x B. yp(x) = Ax^3 + Bx^2 + Cx + Dxe^2xC. yp(x) = Ax^2 +Be^2x D. yp(x) = A+Be^2x +Ce^−x E. yp(x) = Ax^2 +Bx+C +(Dx+E)e^2xarrow_forwardDistance Between Two Ships Two ships leave the same port at noon. Ship A sails north at 17 mph, and ship B sails east at 11 mph. How fast is the distance between them changing at 1 p.m.? (Round your answer to one decimal place.) 20.3 X mph Need Help? Read It Watch It SUBMIT ANSWERarrow_forward
- practice problem please help!arrow_forwardFind the first and second derivatives of the function. f(u) = √7 3u − 3 f'(u) 2 (7-34) (½) f"(u) = 9 4(7-3u) 32 X Need Help? Read It Watch It SUBMIT ANSWERarrow_forward11. Consider the 2nd-order non-homogeneous differential equation y′′ − 4y′ + 3y = et + t2What is the complementary (or homogeneous) solution?A. yc = c1e^t + c2t^2 B. yc = c1e^−t + c2e^−3t C. yc = c1e^t + c2e^3t D. yc = c1e^t + c2e^−3tarrow_forward
- 5. A trial solution for the non-homogeneous equation y′′ + y′ − 2y = e^x isA. Ae^x B. Ae^x+ Be^−2x C. Ae^x + Be^−x D. Axe^x E. None of these.arrow_forward14. Write u = - sint-cost in the form u = C cos(t - a) with C > 0 and 0 ? PAUSE Z X C VI B N Marrow_forward19. If the method of undetermined coefficients is used, the form of a particular solution ofy^(4) − y = e^−t + 3 sin(t) isA. yp(t) = Ate^−t + B cos(t) + C sin(t)B. yp(t) = At^2e^−t + B cos(t) + C sin(t)C. yp(t) = Ate^−t + Bt cos(t) + Ct sin(t)D. yp(t) = At^2e^−t + Bt cos(t) + Ct sin(t)E. yp(t) = Ate^−t + Bt sin(t)arrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning





