Concept explainers
a.
To determine the regression feature of a graphing utility to find a linear model for the data and to check whether the graph is linear or not.
a.

Answer to Problem 34E
The data does not appears linear with the data given.
Explanation of Solution
Given:
The given data for the linear model are (0,78.0),(5,66.0),(10,57.5),(15,51.2),(20,46.3),(25,42.5),(30,39.6)
Graph:
Interpretation: From the graph, the expression for the temperature is
b.
To determine the regression feature of graphing utility to plot the data and graph the model to find a quadratic model and to explain why it might not the good fit model for predicting the temperature of the liquid.
b.

Answer to Problem 34E
The graph shown below shows the quadratic model for the given data and it does not fit for predicting the temperature of the liquid.
Explanation of Solution
Given:
The given data for the linear model are (0,78.0),(5,66.0),(10,57.5),(15,51.2),(20,46.3),(25,42.5),(30,39.6)
Graph:
Interpretation: From the graph, the expression for the temperature is
c.
To determine the regression feature of graphing utility to find a exponential model for the data and to plot the original data and graph the model in the same viewing window.
c.

Answer to Problem 34E
Explanation of Solution
Given:
The given data for the linear model are (0,78.0),(5,66.0),(10,57.5),(15,51.2),(20,46.3),(25,42.5),(30,39.6)
Graph:
Calculation: using the points to subtract the exponential model is
Then add the point 21 to shift the graph upward.
d.
To explain why the procedure used in part© necessary for finding the exponential model.
d.

Answer to Problem 34E
If the original points were used then the exponential model will be
Explanation of Solution
Given:
The given data for the linear model are (0,78.0),(5,66.0),(10,57.5),(15,51.2),(20,46.3),(25,42.5),(30,39.6)
If the original plot were used then the model will be
Chapter 3 Solutions
PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
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