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Concept explainers
Interpretation:
The more acidic compound has to be predicted among the given pair of compound.
Concept Introduction:
Acids donate protons, base accepts protons. The strength of the acid can be said by finding the willingness of the acid to give proton. An acid giving away the proton can be represented in the form of equation as shown below,
If the acid “HA” is very much willing to give the proton it holds means then it is known as a strong acid. If it is not very much willing means it is a weak acid. The strength of the acid can be figured out by looking into the conjugate base that is formed on removal of proton. After loss of proton, a negative charge will be created. If the formed negative charge is more stabilized means then the acid is a strong acid and if it is not stabilized means then it is a weak acid.
There are few factors which determine the strength of the acid and they are,
- What atom the charge is present
- Resonance
- Induction
- Orbitals
If the charge is on a more electronegative atom, then it is stabilized more. Hence, the compound will be more acidic.
If the negative charge is made to participate in resonance, then the negative charge will be stabilized. This increases the stability of the conjugate base and in turn the compound will be more acidic.
Pull of the electron density by the more electronegative atom is known as induction. The inductive effects can stabilize or destabilize the conjugate base. If the inductive effect stabilize the conjugate base, then the compound will be acidic.
The orbital in which the negative charge is present also plays an important role in stability of the conjugate base. A negative charge on
In order to find whether the compound is more acidic or not, the first step is to remove the proton to form conjugate base. Then look for the above four factors.
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Chapter 3 Solutions
Organic Chemistry As a Second Language: First Semester Topics
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- How can you distinguish between each pair of compounds below using IR? Cite a bond and frequency that can be used to distinguish. Provide thorough steps and explanation.arrow_forwardPropagation of uncertainty. Find the absolute and percent relative uncertainty assuming the ±-values are random error. 65±0.04 + 5.28±0.02 – 1.12±0.01 6±0.9 × 50.2±0.7 ÷ 13.8±0.5 [4.88±0.07 + 3.22±0.05] / 1.53±0.02arrow_forwardMatch to correct spectrum and explain the bonds and frequencies used to tell what spectrum connected to the given option. Thanks.arrow_forward
- Draw the virtual orbitals for the planar and pyramidal forms of CH3 and for the linear and bent forms of CH2arrow_forwardQ2: Draw the molecules based on the provided nomenclatures below: (2R,3S)-2-chloro-3-methylpentane: (2S, 2R)-2-hydroxyl-3,6-dimethylheptane:arrow_forwardQ3: Describes the relationship (identical, constitutional isomers, enantiomers or diastereomers) of each pair of compounds below. ག H CH3 OH OH CH3 H3C OH OH OH ////////// C CH3 CH3 CH3 CH3 H3C CH 3 C/III..... Physics & Astronomy www.physics.northweste COOH H нош..... H 2 OH HO CH3 HOOC H CH3 CH3 CH3 Br. H H Br and H H H Harrow_forward
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