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Concept explainers
Interpretation:
The two highlighted proton in the given compound has to be compared and which is more acidic has to be determined.
Concept Introduction:
Acids donate protons, base accepts protons. The strength of the acid can be said by finding the willingness of the acid to give proton. An acid giving away the proton can be represented in the form of equation as shown below,
If the acid “HA” is very much willing to give the proton it holds means then it is known as a strong acid. If it is not very much willing means it is a weak acid. The strength of the acid can be figured out by looking into the conjugate base that is formed on removal of proton. After loss of proton, a negative charge will be created. If the formed negative charge is more stabilized means then the acid is a strong acid and if it is not stabilized means then it is a weak acid.
There are few factors which determine the strength of the acid and they are,
- What atom the charge is present
- Resonance
- Induction
- Orbitals
If the charge is on a more electronegative atom, then it is stabilized more. Hence, the compound will be more acidic.
If the negative charge is made to participate in resonance, then the negative charge will be stabilized. This increases the stability of the conjugate base and in turn the compound will be more acidic.
Pull of the electron density by the more electronegative atom is known as induction. The inductive effects can stabilize or destabilize the conjugate base. If the inductive effect stabilize the conjugate base, then the compound will be acidic.
The orbital in which the negative charge is present also plays an important role in stability of the conjugate base. A negative charge on
In order to find whether the compound is more acidic or not, the first step is to remove the proton to form conjugate base. Then look for the above four factors.
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Chapter 3 Solutions
Organic Chemistry As a Second Language: First Semester Topics
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- Devise a synthesis to prepare 4-tert-butyl-2-nitrotoluene from toluene. Complete the following reaction scheme. Part 1 of 4 Step 1 Step 2 A B Draw the structure for compound B, 4-tert-butyl-2-nitrotoluene. Click and drag to start drawing a structure. 'O Х ப:arrow_forwardWhat is N hybridized? sp3 or sp2? whyarrow_forwardDate Unknown o Hydrated Salt Lab Sec. Name Trial I Trial 2 1. Mass of fired crucible and lid (g) 2. Mass of fired crucible, lid, and hydrated sah (g) 3. Instructor's approval of flame and apparatus 4. Mass of crucible, lid, and anhydrous salt Ist mass measurement (g) 2nd mass measurement (g) 3rd mass measurement (g). Desk No. Trial 3 48.833 46.808 213.692 51.507 9.359 46,615 50.296 48.211 45.351 50.142 48.146 45.1911 50.103 48.132 45.186 5. Final mass of crucible, lid, and anhydrous salt (g) 50.180 4.13 45.243 Calculations 1. Mass of hydrated salt (g) 2. Mass of anhydrous salt (g) 2.674 2.491 2.9239 1.3479 1.2959 1.5519 3. Mass of water lost (g) 1.32791969 1.322g 4. Percent by mass of volatile water in hydrated salt (%) 49.6% 48% 216.9% 5. Average percent HO in bydrated salt (%H,O) 5. Standard deviation of %H,O Relative standard deviation of %H,O in hydrated salt (RSD) how calculations on next page. 48.17% Data Analysis, B Data Analysis, C Data Analysis, D Experiment 5 89arrow_forward
- Considering the irregular electronic configurations we discussed for certain transitionmetals, think about the possibility of silicon (Si) having a [Ne]3s 2 3p 2 configuration vs.[Ne]3s 1 3p 3. Discuss the pros and cons of both configurations. Which one does Si actuallyadopt and why?arrow_forward(5 Pts) Currently, the last element in the periodic table is number 118, oganesson (Og). Channel your inner Dimitri Mendeleev and predict element 119’s electronic configuration, atomic mass, density, and either melting or boiling point. Justify your answers.arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
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