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The 800-lb tree trunk is known to have insect damage near point O, so the winch arrangement shown is used to fell the tree with no cutting. If winch
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- The 1200-lb homogeneous block is placed on rollers and pushed up the 10 incline at constant speed. Determine the force P and the roller reactions at A and B.arrow_forwardWith the 360-lb cylindrical part Pin its grip, the robotic arm pivots about O through the range -45° ≤ 0 ≤ 45° with the angle at A locked at 120%. Determine and plot (as a function of e) the moment at O due to the combined effects of the 360-lb part P, the 100-lb weight of member OA (mass center at G₁), and the 60-lb weight of member AB (mass center at G₂). The end grip is included as a part of member AB. The lengths L₁ and L2 are 2.8 ft and 2.0 ft, respectively. What is the maximum absolute value of Mo and at what value of 0 does this maximum occur? The moment is positive if counterclockwise, negative if clockwise. After you have the plot, answer the questions. A lb-ft lb-ft lb-ft 8 77 5/2 + T G₁ To (M 120⁰ G₂ B 0 Questions: When 0 = -26°, Mo= i When 0 = 6°, Mo= i When 0 = 20°, Mo= i The maximum absolute value Momax = lb-ft at 0= iarrow_forwardThe wom an maint ains a slow steady motion over the indicated 135° range as she exercises her triceps muscle. For this condition, the tension in the cable can be assumed to be constant at W = 10 lb. Determine and plot the moment M of the cable tension as applied at A about the elbow joint O over the range 0<0< 135°. Find the maximum value of M and the value of 0 for which it occurs: Hint: you can use the computer to draw the graph M versus 0 and sketch it on your paper. B 21" 13" 45° W 24"-arrow_forward
- Determine the internal normal force, shear force, and moment at points F and E in the frame. The crate weighs 300 lb. 4 ft 1.5 ft 1.5 ft | 15 ft B 1.5 ft | 1.5 ft D 0.4 ftarrow_forwardWith the 315-lb cylindrical part P in its grip, the robotic arm pivots about O through the range-45 ≤ 0 ≤ 45° with the angle at A locked at 120°. Determine and plot (as a function of 0) the moment at O due to the combined effects of the 315-lb part P, the 105-lb weight of member OA (mass center at G₁), and the 35-lb weight of member AB (mass center at G₂). The end grip is included as a part of member AB. The lengths L₁ and L2 are 2.3 ft and 1.6 ft, respectively. What is the maximum absolute value of Mo and at what value of 8 does this maximum occur? The moment is positive if counterclockwise, negative if clockwise. After you have the plot, answer the questions. 5 15/01 4 120 G₂ Questions: When 8-35°, Mo= i lb-ft When 8 = -6°, Mo= lb-ft When 8 = 19°, Mo= lb-ft 2 iarrow_forwardWith the 260-lb cylindrical part P in its grip, the robotic arm pivots about O through the range –45° < 0 < 45° with the angle at A locked at 120°. Determine and plot (as a function of 0) the moment at O due to the combined effects of the 260-lb part P, the 130-lb weight of member OA (mass center at G1), and the 45-lb weight of member AB (mass center at G2). The end grip is included as a part of member AB. The lengths L1 and L2 are 2.2 ft and 1.8 ft, respectively. What is the maximum absolute value of Mo and at what value of 0 does this maximum occur? The moment is positive if counterclockwise, negative if clockwise. After you have the plot, answer the questions. L2 120° G B Questions: Ib-ft When e = -22°, Mo= When 8 = 3°, Mo = i Ib-ft Ib-ft When e = 19°, Mo= i Ib-ft at 0 = i The maximum absolute value Momaxarrow_forward
- With the 370-lb cylindrical part P in its grip, the robotic arm pivots about O through the range -45° ≤ 0 ≤ 45° with the angle at A locked at 120°. Determine and plot (as a function of 0) the moment at O due to the combined effects of the 370-lb part P, the 125-lb weight of member OA (mass center at G₁), and the 45-lb weight of member AB (mass center at G₂). The end grip is included as a part of member AB. The lengths L₁ and L2 are 3.3 ft and 2.5 ft, respectively. What is the maximum absolute value of Mo and at what value of does this maximum occur? The moment is positive if counterclockwise, negative if clockwise. After you have the plot, answer the questions. LA lb-ft lb-ft lb-ft 0 2 52 120° G₂ 35 L₂ L₂ 2 B Questions: When 0-18°, Mo= i When 8 = -5°, Mo= i When 0= 19°, Mo= i The maximum absolute value Momax = H lb-ft at 0= iarrow_forwardWith the 360-lb cylindrical part P in its grip, the robotic arm pivots about O through the range -45° ≤ 0 ≤ 45° with the angle at A locked at 120°. Determine and plot (as a function of 0) the moment at O due to the combined effects of the 360-lb part P, the 100-lb weight of member OA (mass center at G₁), and the 60-lb weight of member AB (mass center at G₂). The end grip is included as a part of member AB. The lengths L₁ and L₂ are 2.8 ft and 2.0 ft, respectively. What is the maximum absolute value of Mo and at what value of 0 does this maximum occur? The moment is positive if counterclockwise, negative if clockwise. After you have the plot, answer the questions. lb-ft lb-ft lb-ft 52 120⁰ G₂ G₁ T! L₂ L₂ B Mi Questions: When 0 = -26°, Mo= When 0 = 6°, Mo When 0 = 20°, Mo= i The maximum absolute value Momax = 1834.87 lb-ft at 0= 21.60arrow_forwardAlso need help drawing the shear and moment diagrams.arrow_forward
- Can somebody explain this problem step by step ? I will apprecite any help. Thanksarrow_forwardA.The bar of negligible weight is supported by two springs, each having a stiffness k = 98 N/m. If the springs are originally unstretched, and the force is vertical as shown, determine the angle the bar makes with the horizontal, when the 31-N force is applied to the bar. B.Determine the stiffness k of each spring so that the 32-N force causes the bar to tip = 13.6° when the force is applied. Originally the bar is horizontal and the springs are unstretched. Neglect the weight of the bar.arrow_forwardPlease helparrow_forward
- International Edition---engineering Mechanics: St...Mechanical EngineeringISBN:9781305501607Author:Andrew Pytel And Jaan KiusalaasPublisher:CENGAGE L