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Math Calculus APPLIED CALCULUS-PRINT COMPANION (LL)

The method in way it is possible for the total cholesterol of the patient to increase but the cholesterol ratio to remain constant if cholesterol ratio is given by the ratio of good cholesterol G ( t ) to the total cholesterol R ( t ) = G ( t ) T ( t ) . The safety situation is when the cholesterol ratio is R ( t ) > 1 5 .

The method in way it is possible for the total cholesterol of the patient to increase but the cholesterol ratio to remain constant if cholesterol ratio is given by the ratio of good cholesterol G ( t ) to the total cholesterol R ( t ) = G ( t ) T ( t ) . The safety situation is when the cholesterol ratio is R ( t ) > 1 5 .

Solution Summary: The author explains that the cholesterol ratio is constant if the rate of change of total cholesterol is equal to the good cholesterol.

APPLIED CALCULUS-PRINT COMPANION (LL)

APPLIED CALCULUS-PRINT COMPANION (LL)

6th Edition

ISBN: 9781119275565

Author: Hughes-Hallett

Publisher: WILEY

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Chapter 3.4, Problem 46P

(a)

To determine

To find:

The method in way it is possible for the total cholesterol of the patient to increase but the cholesterol ratio to remain constant if cholesterol ratio is given by the ratio of good cholesterol G(t) to the total cholesterol R(t)=G(t)T(t). The safety situation is when the cholesterol ratio is R(t)>15.

(b)

To determine

To calculate:

The rate of change of total cholesterol level in the first week of the diet. On January 1, the total cholesterol is 120 mgdl and the good cholesterol level is 30 mgdl Although the cholesterol ratio is in safety limit but the doctor prefers that the good cholesterol increases with 40 mgdl. In order to change the diet-plan the good cholesterol needs to change with the rate 1 mgdl. Cholesterol ratio is given by the ratio of good cholesterol G(t) to the total cholesterol R(t)=G(t)T(t). The safety situation is when the cholesterol ratio is R(t)>15.

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Chapter 3.4, Problem 45P

Chapter 3.4, Problem 47P

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Question 1: If a barometer were built using oil (p = 0.92 g/cm³) instead of mercury (p = 13.6 g/cm³), would the column of oil be higher than, lower than, or the same as the column of mercury at 1.00 atm? If the level is different, by what factor? Explain. (5 pts) Solution: A barometer works based on the principle that the pressure exerted by the liquid column balances atmospheric pressure. The pressure is given by: P = pgh Since the atmospheric pressure remains constant (P = 1.00 atm), the height of the liquid column is inversely proportional to its density: Step 1: Given Data PHg hol=hgx Poil • Density of mercury: PHg = 13.6 g/cm³ Density of oil: Poil = 0.92 g/cm³ • Standard height of mercury at 1.00 atm: hμg Step 2: Compute Height of Oil = 760 mm = 0.760 m 13.6 hoil = 0.760 x 0.92 hoil = 0.760 × 14.78 hoil = 11.23 m Step 3: Compare Heights Since oil is less dense than mercury, the column of oil must be much taller than that of mercury. The factor by which it is taller is: Final…

Chapter 3 Solutions

APPLIED CALCULUS-PRINT COMPANION (LL)

Ch. 3.1 - Prob. 1P Ch. 3.1 - Prob. 2P Ch. 3.1 - Prob. 3P Ch. 3.1 - Prob. 4P Ch. 3.1 - Prob. 5P Ch. 3.1 - Prob. 6P Ch. 3.1 - Prob. 7P Ch. 3.1 - Prob. 8P Ch. 3.1 - Prob. 9P Ch. 3.1 - Prob. 10P

Ch. 3.1 - Prob. 11P Ch. 3.1 - Prob. 12P Ch. 3.1 - Prob. 13P Ch. 3.1 - Prob. 14P Ch. 3.1 - Prob. 15P Ch. 3.1 - Prob. 16P Ch. 3.1 - Prob. 17P Ch. 3.1 - Prob. 18P Ch. 3.1 - Prob. 19P Ch. 3.1 - Prob. 20P Ch. 3.1 - Prob. 21P Ch. 3.1 - Prob. 22P Ch. 3.1 - Prob. 23P Ch. 3.1 - Prob. 24P Ch. 3.1 - Prob. 25P Ch. 3.1 - Prob. 26P Ch. 3.1 - Prob. 27P Ch. 3.1 - Prob. 28P Ch. 3.1 - Prob. 29P Ch. 3.1 - Prob. 30P Ch. 3.1 - Prob. 31P Ch. 3.1 - Prob. 32P Ch. 3.1 - Prob. 33P Ch. 3.1 - Prob. 34P Ch. 3.1 - Prob. 35P Ch. 3.1 - Prob. 36P Ch. 3.1 - Prob. 37P Ch. 3.1 - Prob. 38P Ch. 3.1 - Prob. 39P Ch. 3.1 - Prob. 40P Ch. 3.1 - Prob. 41P Ch. 3.1 - Prob. 42P Ch. 3.1 - Prob. 43P Ch. 3.1 - Prob. 44P Ch. 3.1 - Prob. 45P Ch. 3.1 - Prob. 46P Ch. 3.1 - Prob. 47P Ch. 3.1 - Prob. 48P Ch. 3.1 - Prob. 49P Ch. 3.1 - Prob. 50P Ch. 3.1 - Prob. 51P Ch. 3.1 - Prob. 52P Ch. 3.1 - Prob. 53P Ch. 3.1 - Prob. 54P Ch. 3.1 - Prob. 55P Ch. 3.1 - Prob. 56P Ch. 3.1 - Prob. 57P Ch. 3.1 - Prob. 58P Ch. 3.1 - Prob. 59P Ch. 3.1 - Prob. 60P Ch. 3.1 - 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Prob. 24FOP Ch. 3 - Prob. 25FOP Ch. 3 - Prob. 26FOP Ch. 3 - Prob. 27FOP Ch. 3 - Prob. 28FOP Ch. 3 - Prob. 29FOP Ch. 3 - Prob. 30FOP Ch. 3 - Prob. 31FOP Ch. 3 - Prob. 32FOP Ch. 3 - Prob. 33FOP Ch. 3 - Prob. 34FOP Ch. 3 - Prob. 35FOP Ch. 3 - Prob. 36FOP Ch. 3 - Prob. 37FOP Ch. 3 - Prob. 38FOP Ch. 3 - Prob. 39FOP Ch. 3 - Prob. 40FOP Ch. 3 - Prob. 41FOP Ch. 3 - Prob. 42FOP Ch. 3 - Prob. 43FOP Ch. 3 - Prob. 44FOP Ch. 3 - Prob. 45FOP Ch. 3 - Prob. 46FOP Ch. 3 - Prob. 47FOP Ch. 3 - Prob. 48FOP Ch. 3 - Prob. 49FOP Ch. 3 - Prob. 50FOP Ch. 3 - Prob. 51FOP Ch. 3 - Prob. 52FOP Ch. 3 - Prob. 53FOP Ch. 3 - Prob. 54FOP Ch. 3 - Prob. 55FOP Ch. 3 - Prob. 56FOP Ch. 3 - Prob. 57FOP Ch. 3 - Prob. 58FOP Ch. 3 - Prob. 59FOP Ch. 3 - Prob. 60FOP Ch. 3 - Prob. 61FOP Ch. 3 - Prob. 62FOP Ch. 3 - Prob. 63FOP

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