Explanation Given: Function y = sin ( x 2 ) . Formula Used: Formula of derivatives are as follows: d d x ( f ( u ) ) = d d u ( f ( u ) ) × d u d x , chain rule d d x ( x n ) = n x n − 1 d d x c . f ( x ) = c . d d x f ( x ) d d x ( sin x ) = cos x Calculation: Function is given as y = sin ( x 2 )

6th Edition

ISBN: 9781119275565

Author: Hughes-Hallett

Publisher: WILEY

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Chapter 3.5, Problem 12P

To determine

To find derivative of the below function.

y=sin(x2)

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Chapter 3.5, Problem 11P

Chapter 3.5, Problem 13P

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Each of the following statements is an attempt to show that a given series is convergent or divergent using the Comparison Test (NOT the Limit Comparison Test.) For each statement, enter C (for "correct") if the argument is valid, or enter | (for "incorrect") if any part of the argument is flawed. (Note: if the conclusion is true but the argument that led to it was wrong, you must enter I.) ☐ 1. For all n > 1, seriesΣ In(n) In(n) converges. 2, 1, arctan(n) the series arctan(n) n³ ☐ 4. For all n > 1, 123 converges. 1 n ln(n) series In(n) diverges. 2n . and the seriesΣconverges, so by the Comparison Test, 2, 3, and the series converges, so by the Comparison Test, the series-3 1 converges. ☐ 6. For all n > 2, In(n) >, and the series Σ converges, so by the Comparison Test, the seriesΣ In(n) converges.

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Chapter 3 Solutions

APPLIED CALCULUS-PRINT COMPANION (LL)

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To find derivative of the below function. y = sin ( x 2 )

Solution Summary: The author explains how the function is given as y=mathrmsin(x2).

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To find derivative of the below function.

y=sin(x2)

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Chapter 3 Solutions

To find derivative of the below function. y = sin ( x 2 )

Solution Summary: The author explains how the function is given as y=mathrmsin(x2).

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To find derivative of the below function. y=sin(x2)

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Chapter 3 Solutions

To find derivative of the below function.

y=sin(x2)