Explanation Given: Function f ( t ) = 6.8 e − 0.5 t . Formula Used: Relative rate of change of f ( t ) is given as d d t ln f ( t ) . Calculation: Function is given as f ( t ) = 6.8 e − 0.5 t . Taking natural logarithm on both sides, we have ln f ( t ) = ln ( 6.8 e − 0.5 t ) ln f ( t ) = ln ( 6.8 ) + ln ( e − 0.5 t ) ln f ( t ) = ln ( 6.8 ) + ( − 0.5 t ) ln f ( t ) = ln ( 6

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ISBN: 9781119275565

Author: Hughes-Hallett

Publisher: WILEY

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Chapter 3.3, Problem 30P

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To findthe relative rate of change of f(t) using the formula ddtlnf(t).

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Chapter 3.3, Problem 29P

Chapter 3.3, Problem 31P

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According to Newton's law of universal gravitation, the force F between two bodies of constant mass GmM m and M is given by the formula F = , where G is the gravitational constant and d is the d² distance between the bodies. a. Suppose that G, m, and M are constants. Find the rate of change of force F with respect to distance d. F' (d) 2GmM b. Find the rate of change of force F with gravitational constant G = 6.67 × 10-¹¹ Nm²/kg², on two bodies 5 meters apart, each with a mass of 250 kilograms. Answer in scientific notation, rounding to 2 decimal places. -6.67x10 N/m syntax incomplete.

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To findthe relative rate of change of f ( t ) using the formula d d t ln f ( t ) .

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To findthe relative rate of change of f(t) using the formula ddtlnf(t).

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Chapter 3 Solutions