Explanation Given: Function Z ( t ) = 300 t 2 Formula Used: Formulas of derivatives are as follows: d d x ( c ) = 0 , where c is a constant. d d x ( x n ) = n x n − 1 d d x { c . f ( x ) } = c . d d x f ( x ) Calculation: Function is given as, Z ( t ) = 300 t 2 Derivative of the above function is calculated as: d d t Z ( t ) = d d t ( 300 t 2 ) Z ′ ( t ) = 300 d d t </

6th Edition

ISBN: 9781119275565

Author: Hughes-Hallett

Publisher: WILEY

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Differential Equations

Have you ever observed the movement of the satellites and rockets or how the planets go around the sun in their orbits? How will you determine their motion? Definitely they follow some scientific laws and these kinds of problems are framed as differentia…

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Chapter 3.1, Problem 49P

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To find the number of Zebra mussels in the bay after four months and the rate at which the population is growing at t=4 with t being the number of months.

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Chapter 3.1, Problem 48P

Chapter 3.1, Problem 50P

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To find the number of Zebra mussels in the bay after four months and the rate at which the population is growing at t = 4 with t being the number of months.

Solution Summary: The author calculates the number of Zebra mussels in the bay after four months and the rate at which the population is growing at t=4.

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To find the number of Zebra mussels in the bay after four months and the rate at which the population is growing at t=4 with t being the number of months.

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Chapter 3 Solutions