Explanation Given: q = f ( p ) = 10000 e − 0.25 p Calculation: Differentiate the given function with respect to p. f ( t ) = d d t ( 10000 e − 0.25 p ) We know that d d x ( e − a x ) = − a ⋅ e − a x Here, a = − 0.25 f ' ( p ) = 10000 ( − 0.25 ) e − 0.25 p f ' ( p ) = − 2500 e − 0.25 p Substitute p = 2 in f ( p ) f ( 2 ) = 10000 e − 0.25 ( 2 ) f ( 2 ) = 10000 e − 0

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ISBN: 9781119275565

Author: Hughes-Hallett

Publisher: WILEY

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Chapter 3.2, Problem 44P

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To find and explain f(2) and f'(2).

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Chapter 3.2, Problem 43P

Chapter 3.2, Problem 45P

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To find and explain f ( 2 ) and f ' ( 2 ) .

Solution Summary: The author compares the values of f(2) and '(2)=-1500.

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To find and explain f(2) and f'(2).

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Chapter 3 Solutions