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Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337553292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Question
Chapter 34, Problem 27P
(a)
To determine
The Critical angle for cubic zirconia.
(b)
To determine
The critical angle for flint glass.
(c)
To determine
The critical angle for the ice.
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Students have asked these similar questions
For 589-nm light, calculate the critical angle for the following materials surrounded by air: (a) cubic zirconia, (b) flint glass, and (c) ice.
For 589nm light, calculate the critical angle for the following materials surrounded by air.
(a) diamond, n = 2.419
(b) flint glass, n = 1.66
(c) ice, n = 1.309
For 589-nm light, calculate the critical angle for the following materials surrounded by air.
(a) cubic zirconia (n = 2.20)
(b) gallium phosphide (n = 3.50)
(c) polystyrene (n = 1.49)
Chapter 34 Solutions
Physics for Scientists and Engineers with Modern Physics
Ch. 34.3 - Prob. 34.1QQCh. 34.4 - If beam is the incoming beam in Figure 34.10b,...Ch. 34.4 - Light passes from a material with index of...Ch. 34.6 - Prob. 34.4QQCh. 34.7 - Prob. 34.5QQCh. 34 - In an experiment to measure the speed of light...Ch. 34 - Prob. 2PCh. 34 - As a result of his observations, Ole Roemer...Ch. 34 - Prob. 4PCh. 34 - You are working for an optical research company...
Ch. 34 - Prob. 6PCh. 34 - Prob. 7PCh. 34 - Prob. 8PCh. 34 - Prob. 9PCh. 34 - A ray of light strikes a flat block of glass (n =...Ch. 34 - Prob. 11PCh. 34 - Prob. 12PCh. 34 - Prob. 13PCh. 34 - Prob. 14PCh. 34 - When you look through a window, by what time...Ch. 34 - Prob. 16PCh. 34 - You have just installed a new bathroom in your...Ch. 34 - Prob. 18PCh. 34 - Prob. 19PCh. 34 - Prob. 20PCh. 34 - Prob. 21PCh. 34 - A submarine is 300 m horizontally from the shore...Ch. 34 - Prob. 23PCh. 34 - Prob. 24PCh. 34 - Prob. 25PCh. 34 - Prob. 26PCh. 34 - Prob. 27PCh. 34 - Prob. 28PCh. 34 - Prob. 29PCh. 34 - Prob. 30PCh. 34 - An optical fiber has an index of refraction n and...Ch. 34 - Prob. 32APCh. 34 - How many times will the incident beam in Figure...Ch. 34 - Prob. 34APCh. 34 - Prob. 35APCh. 34 - Prob. 36APCh. 34 - Prob. 37APCh. 34 - Prob. 38APCh. 34 - Prob. 39APCh. 34 - A light ray enters the atmosphere of a planet and...Ch. 34 - Prob. 41APCh. 34 - Prob. 42APCh. 34 - Prob. 43APCh. 34 - Prob. 44APCh. 34 - Prob. 45APCh. 34 - Prob. 46APCh. 34 - Prob. 47APCh. 34 - Prob. 48APCh. 34 - Prob. 49APCh. 34 - Figure P34.50 shows a top view of a square...Ch. 34 - Prob. 51APCh. 34 - Prob. 52CPCh. 34 - Prob. 53CPCh. 34 - Pierre de Fermat (16011665) showed that whenever...Ch. 34 - Prob. 55CPCh. 34 - Prob. 56CPCh. 34 - Prob. 57CP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- How many times will the incident beam in Figure P34.33 (page 922) be reflected by each of the parallel mirrors? Figure P34.33arrow_forwardLight enters a prism of crown glass and refracts at an angle of 5.00 with respect to the normal at the interface. The crown glass has a mean index of refraction of 1.51. It is combined with one flint glass prism (n = 1.65) to produce no net deviation. a. Find the apex angle of the flint glass. b. Assume the index of refraction for violet light (v = 430 nm) is nv = 1.528 and the index of refraction for red light (r = 768 nm) is nr = 1.511 for crown glass. For flint glass using the same wavelengths, nv = 1.665 and nr = 1.645. Find the net dispersion.arrow_forwardA plano-convex lens has index of refraction n. The curved side of the lens has radius of curvature R and rests on a flat glass surface of the same index of refraction, with a film of index nflim between them, as shown in Figure P36.42. The lens is illuminated from above by light of wavelength . Show that the dark Newtons rings have radii given approximately by r=mRnfilm where r R and m is an integer. Figure P36.42arrow_forward
- A person looking into an empty container is able to see the far edge of the containers bottom, as shown in Figure P22.23a. The height of the container is h, and its width is d. When the container is completely filled with a fluid of index of refraction n and viewed from the same angle, the person can see the center of a coin at the middle of the containers bottom, as shown in Figure P22.23b. (a) Show that the ratio h/d is given by hd=n214n2 (b) Assuming the container has a width of 8.00 cm and is filled with water, use the expression above to find the height of the container.arrow_forwardFor 589-nm light, calculate the critical angle for the following materials surrounded by air. (a) cubic zirconia (n = 2.20) (b) crown glass (n = 1.52) (c) polystyrene (n = 1.49)arrow_forwardFor 589-nm light, calculate the critical angle for the following materials surrounded by air. (a) diamond (n = 2.419) (b) gallium phosphide (n = 3.50) 0 (c) polystyrene (n = 1.49) 0arrow_forward
- In the figure, light is incident at angle 0, = 41° on a boundary between two transparent materials. Some of the light travels down through the next three layers of transparent materials, while some of it reflects upward and then escapes into the air. If nį = 1.30, n2 = 1.40, n3 = 1.32 and n4 = 1.43, what is the value of 04? 20. Air ng 74 (a) 28.8° (b) 32.8° (c) 36.6° (d) 40.6° (e) None of the abovearrow_forwardCh. 34arrow_forwardWhat is the angle of incidence on an air-to-glass boundary if the angle of refraction in the glass (n= 1.52) is 25º?arrow_forward
- A layer of benzene 1n = 1.502 that is 4.20 cm deep floats on water 1n = 1.332 that is 5.70 cm deep. What is the apparent distance from the upper benzene surface to the bottom of the water when you view these layers at normal incidence?arrow_forwardPlease asaparrow_forwardIn the figure, light is incident at angle 6, = 41.0° on a boundary between two transparent materials. Some of the light travels down through the next three layers of transparent materials, while some of it reflects upward and then escapes into the air. If n1 = 1.28, n, = 1.38, ng = 1.30 and n4 = 1.43, what is the value of (a) 05 and (b) 04? Air (a) 05 = NumberT32.02 UnitsTo (degrees) (b)04 = NumberT43.1 Units (degrees)arrow_forward
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