
Concept explainers
(a)
To calculate: The interval at which P is moving to the left, right and is standing still.
(a)

Answer to Problem 10E
The particle is moving right in the interval
The particle is standing still in the interval
The particle is moving left in the interval
Explanation of Solution
Given Information: The movement of the particle on the number line.
Calculation:
The derivative of the movement of the particle is positive in the interval
Therefore, the particle is moving right in the interval
Horizontal line represents that the derivative of the movement of the particle is 0. That is, velocity is 0.
So, the particle is standing still in the interval
The derivative of the movement of the particle is negative in the interval
Therefore, the particle is moving left in the interval
Conclusion:
The particle is moving right in the interval
The particle is standing still in the interval
The particle is moving left in the interval
(b)
To draw: The graph for particle’s velocity and speed.
(b)

Answer to Problem 10E
The graph of the velocity and the speed of the graph is shown
Explanation of Solution
Given Information: The movement of the particle on the number line.
Calculation:
The slope of the graph shows the velocity of the particle and the slope of the particle is such that it is moving right in the interval
The graph can be sketched as follows:
The velocity can be negative, but speed is the absolute value of the velocity and hence can never be negative.
The graph of the speed is,
Conclusion:
The graph of the velocity and the speed of the graph is shown above.
Chapter 3 Solutions
Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)
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