Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)

4th Edition

ISBN: 9780133178579

Author: Ross L. Finney

Publisher: PEARSON

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Question

Chapter 3.3, Problem 4QQ

(a)

To determine

To Calculate: All the points when f has horizontal tangents.

(a)

Expert Solution

Answer to Problem 4QQ

The horizontals tangents passes to the points are (0,0) , (2,−4) and (−2,−4) .

Explanation of Solution

Given Information:

The function is f(x)=x4−4x2 .

Formula Used:

Power rule of derivative:

ddxxn=nxn−1

Calculation:

The function is f(x)=x4−4x2 .

Find the derivative.

f′(x)=4x3−8x

Substitute the derivative of the function equal to 0, to find the values of x .

4x3−8x=0

Take 4x common from left hand side.

4x(x2−2)=0

That is,

4x=0 or (x2−2)=0x=0 or x2=2x=0 or x=±2

Substitute 0 for x in the function, to find the value of f(0) .

f(0)=(0)4−4(0)2=0−0=0

Thus, the point is (0,0) .

Substitute 2 for x in the function, to find the value of f(2) .

f(2)=(2)4−4(2)2=4−8=−4

Thus, the point is (2,−4) .

Substitute −2 for x in the function, to find the value of f(−2) .

f(−2)=(−2)4−4(−2)2=4−8=−4

Thus, the point is (−2,−4) .

Hence, the horizontals tangents passes to the points are (0,0) , (2,−4) and (−2,−4) .

(b)

To determine

To calculate: The equation of the tangent line when x=1 .

(b)

Expert Solution

Answer to Problem 4QQ

The equation of the tangent is y=−4x+1 .

Explanation of Solution

Given Information:

The function is f(x)=x4−4x2 .

Formula Used:

Power rule of derivative:

ddxxn=nxn−1

Calculation:

The function is f(x)=x4−4x2 .

Find the derivative.

f′(x)=4x3−8x

Substitute 1 for x in the function, to find the value of f(1) .

f(1)=(1)4−4(1)2=1−4=−3

Thus, the tangent passes through the point is (1,−3) .

Substitute 1 for x in the function f′(1) , to find the value of slope.

f′(1)=4(1)3−8(1)=4−8=−4

Thus, the slope is −4 .

Find the equation of the tangentline, when the passing point is (1,−3) and slope is −4 .

Substitute 1 for x1 , −3 for y1 and −4 for m in the equation y−y1=m(x−x1) .

y−(−3)=(−4)(x−1)y+3=−4x+4y=−4x+4−3y=−4x+1

Hence, the equation of the tangent is y=−4x+1 .

(c)

To determine

To calculate: The equation of the normal line when x=1 .

(c)

Expert Solution

Answer to Problem 4QQ

The equation of the normal line is 4y=x−13 .

Explanation of Solution

Given Information:

The function is f(x)=x4−4x2 .

Formula Used:

Power rule of derivative:

ddxxn=nxn−1

Calculation:

The function is f(x)=x4−4x2 .

Find the derivative.

f′(x)=4x3−8x

Substitute 1 for x in the function, to find the value of f(1) .

f(1)=(1)4−4(1)2=1−4=−3

Thus, the tangent passes through the point is (1,−3) .

Substitute 1 for x in the function f′(1) , to find the value of slope.

f′(1)=4(1)3−8(1)=4−8=−4

Thus, the slope is −4 .

The slope of normal is 14 .

Find the equation of the normal line, when the passing point is (1,−3) and slope is 14 .

Substitute 1 for x1 , −3 for y1 and 14 for m in the equation y−y1=m(x−x1) .

y−(−3)=(14)(x−1)y=(14)(x−1)−3y=14x−14−34y=x−13

Hence, the equation of the normal line is 4y=x−13 .

Chapter 3.3, Problem 3QQ

Chapter 3.4, Problem 1QR

Chapter 3 Solutions

Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)

Ch. 3.1 - Prob. 1QR Ch. 3.1 - Prob. 2QR Ch. 3.1 - Prob. 3QR Ch. 3.1 - Prob. 4QR Ch. 3.1 - Prob. 5QR Ch. 3.1 - Prob. 6QR Ch. 3.1 - Prob. 7QR Ch. 3.1 - Prob. 8QR Ch. 3.1 - Prob. 9QR Ch. 3.1 - Prob. 10QR

Ch. 3.1 - Prob. 1E Ch. 3.1 - Prob. 2E Ch. 3.1 - Prob. 3E Ch. 3.1 - Prob. 4E Ch. 3.1 - Prob. 5E Ch. 3.1 - Prob. 6E Ch. 3.1 - Prob. 7E Ch. 3.1 - Prob. 8E Ch. 3.1 - Prob. 9E Ch. 3.1 - Prob. 10E Ch. 3.1 - Prob. 11E Ch. 3.1 - Prob. 12E Ch. 3.1 - Prob. 13E Ch. 3.1 - Prob. 14E Ch. 3.1 - Prob. 15E Ch. 3.1 - Prob. 16E Ch. 3.1 - Prob. 17E Ch. 3.1 - Prob. 18E Ch. 3.1 - Prob. 19E Ch. 3.1 - Prob. 20E Ch. 3.1 - Prob. 21E Ch. 3.1 - Prob. 22E Ch. 3.1 - Prob. 23E Ch. 3.1 - Prob. 24E Ch. 3.1 - Prob. 25E Ch. 3.1 - Prob. 26E Ch. 3.1 - Prob. 27E Ch. 3.1 - Prob. 28E Ch. 3.1 - Prob. 29E Ch. 3.1 - Prob. 30E Ch. 3.1 - Prob. 31E Ch. 3.1 - Prob. 32E Ch. 3.1 - Prob. 33E Ch. 3.1 - Prob. 34E Ch. 3.1 - Prob. 35E Ch. 3.1 - Prob. 36E Ch. 3.1 - Prob. 37E Ch. 3.1 - Prob. 38E Ch. 3.1 - Prob. 39E Ch. 3.1 - Prob. 40E Ch. 3.1 - Prob. 41E Ch. 3.1 - Prob. 42E Ch. 3.1 - Prob. 43E Ch. 3.1 - Prob. 44E Ch. 3.1 - Prob. 45E Ch. 3.2 - Prob. 1QR Ch. 3.2 - Prob. 2QR Ch. 3.2 - Prob. 3QR Ch. 3.2 - Prob. 4QR Ch. 3.2 - Prob. 5QR Ch. 3.2 - Prob. 6QR Ch. 3.2 - Prob. 7QR Ch. 3.2 - Prob. 8QR Ch. 3.2 - Prob. 9QR Ch. 3.2 - Prob. 10QR Ch. 3.2 - Prob. 1E Ch. 3.2 - Prob. 2E Ch. 3.2 - Prob. 3E Ch. 3.2 - Prob. 4E Ch. 3.2 - Prob. 5E Ch. 3.2 - Prob. 6E Ch. 3.2 - Prob. 7E Ch. 3.2 - Prob. 8E Ch. 3.2 - Prob. 9E Ch. 3.2 - Prob. 10E Ch. 3.2 - Prob. 11E Ch. 3.2 - Prob. 12E Ch. 3.2 - Prob. 13E Ch. 3.2 - Prob. 14E Ch. 3.2 - Prob. 15E Ch. 3.2 - Prob. 16E Ch. 3.2 - Prob. 17E Ch. 3.2 - Prob. 18E Ch. 3.2 - Prob. 19E Ch. 3.2 - Prob. 20E Ch. 3.2 - Prob. 21E Ch. 3.2 - Prob. 22E Ch. 3.2 - Prob. 23E Ch. 3.2 - Prob. 24E Ch. 3.2 - Prob. 25E Ch. 3.2 - Prob. 26E Ch. 3.2 - Prob. 27E Ch. 3.2 - Prob. 28E Ch. 3.2 - Prob. 29E Ch. 3.2 - Prob. 30E Ch. 3.2 - Prob. 31E Ch. 3.2 - Prob. 32E Ch. 3.2 - Prob. 33E Ch. 3.2 - Prob. 34E Ch. 3.2 - Prob. 35E Ch. 3.2 - Prob. 36E Ch. 3.2 - Prob. 37E Ch. 3.2 - Prob. 38E Ch. 3.2 - Prob. 39E Ch. 3.2 - Prob. 40E Ch. 3.2 - Prob. 41E Ch. 3.2 - Prob. 42E Ch. 3.2 - Prob. 43E Ch. 3.2 - Prob. 44E Ch. 3.2 - Prob. 45E Ch. 3.2 - Prob. 46E Ch. 3.2 - Prob. 47E Ch. 3.2 - Prob. 48E Ch. 3.3 - Prob. 1QR Ch. 3.3 - Prob. 2QR Ch. 3.3 - Prob. 3QR Ch. 3.3 - Prob. 4QR Ch. 3.3 - Prob. 5QR Ch. 3.3 - Prob. 6QR Ch. 3.3 - Prob. 7QR Ch. 3.3 - Prob. 8QR Ch. 3.3 - Prob. 9QR Ch. 3.3 - Prob. 10QR Ch. 3.3 - Prob. 1E Ch. 3.3 - Prob. 2E Ch. 3.3 - Prob. 3E Ch. 3.3 - Prob. 4E Ch. 3.3 - Prob. 5E Ch. 3.3 - Prob. 6E Ch. 3.3 - Prob. 7E Ch. 3.3 - Prob. 8E Ch. 3.3 - Prob. 9E Ch. 3.3 - Prob. 10E Ch. 3.3 - Prob. 11E Ch. 3.3 - Prob. 12E Ch. 3.3 - Prob. 13E Ch. 3.3 - Prob. 14E Ch. 3.3 - Prob. 15E Ch. 3.3 - Prob. 16E Ch. 3.3 - Prob. 17E Ch. 3.3 - Prob. 18E Ch. 3.3 - Prob. 19E Ch. 3.3 - Prob. 20E Ch. 3.3 - Prob. 21E Ch. 3.3 - Prob. 22E Ch. 3.3 - Prob. 23E Ch. 3.3 - Prob. 24E Ch. 3.3 - Prob. 25E Ch. 3.3 - Prob. 26E Ch. 3.3 - Prob. 27E Ch. 3.3 - Prob. 28E Ch. 3.3 - Prob. 29E Ch. 3.3 - Prob. 30E Ch. 3.3 - Prob. 31E Ch. 3.3 - Prob. 32E Ch. 3.3 - Prob. 33E Ch. 3.3 - Prob. 34E Ch. 3.3 - Prob. 35E Ch. 3.3 - Prob. 36E Ch. 3.3 - Prob. 37E Ch. 3.3 - Prob. 38E Ch. 3.3 - Prob. 39E Ch. 3.3 - 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Prob. 4RE Ch. 3 - Prob. 5RE Ch. 3 - Prob. 6RE Ch. 3 - Prob. 7RE Ch. 3 - Prob. 8RE Ch. 3 - Prob. 9RE Ch. 3 - Prob. 10RE Ch. 3 - Prob. 11RE Ch. 3 - Prob. 12RE Ch. 3 - Prob. 13RE Ch. 3 - Prob. 14RE Ch. 3 - Prob. 15RE Ch. 3 - Prob. 16RE Ch. 3 - Prob. 17RE Ch. 3 - Prob. 18RE Ch. 3 - Prob. 19RE Ch. 3 - Prob. 20RE Ch. 3 - Prob. 21RE Ch. 3 - Prob. 22RE Ch. 3 - Prob. 23RE Ch. 3 - Prob. 24RE Ch. 3 - Prob. 25RE Ch. 3 - Prob. 26RE Ch. 3 - Prob. 27RE Ch. 3 - Prob. 28RE Ch. 3 - Prob. 29RE Ch. 3 - Prob. 30RE Ch. 3 - Prob. 31RE Ch. 3 - Prob. 32RE Ch. 3 - Prob. 33RE Ch. 3 - Prob. 34RE Ch. 3 - Prob. 35RE Ch. 3 - Prob. 36RE Ch. 3 - Prob. 37RE Ch. 3 - Prob. 38RE Ch. 3 - Prob. 39RE Ch. 3 - Prob. 40RE Ch. 3 - Prob. 41RE Ch. 3 - Prob. 42RE Ch. 3 - Prob. 43RE Ch. 3 - Prob. 44RE Ch. 3 - Prob. 45RE Ch. 3 - Prob. 46RE Ch. 3 - Prob. 47RE Ch. 3 - Prob. 48RE Ch. 3 - Prob. 49RE Ch. 3 - Prob. 50RE Ch. 3 - Prob. 51RE Ch. 3 - Prob. 52RE Ch. 3 - Prob. 53RE Ch. 3 - Prob. 54RE Ch. 3 - Prob. 55RE Ch. 3 - Prob. 56RE Ch. 3 - Prob. 57RE Ch. 3 - Prob. 58RE Ch. 3 - Prob. 59RE Ch. 3 - Prob. 60RE Ch. 3 - Prob. 61RE Ch. 3 - Prob. 62RE Ch. 3 - Prob. 63RE Ch. 3 - Prob. 64RE Ch. 3 - Prob. 65RE Ch. 3 - Prob. 66RE Ch. 3 - Prob. 67RE Ch. 3 - Prob. 68RE Ch. 3 - Prob. 69RE Ch. 3 - Prob. 70RE Ch. 3 - Prob. 71RE Ch. 3 - Prob. 72RE Ch. 3 - Prob. 73RE Ch. 3 - Prob. 74RE Ch. 3 - Prob. 75RE Ch. 3 - Prob. 76RE Ch. 3 - Prob. 77RE Ch. 3 - Prob. 78RE Ch. 3 - Prob. 79RE Ch. 3 - Prob. 80RE Ch. 3 - Prob. 81RE Ch. 3 - Prob. 82RE Ch. 3 - Prob. 83RE

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