![Physics for Scientists and Engineers with Modern Physics](https://www.bartleby.com/isbn_cover_images/9781337553292/9781337553292_largeCoverImage.gif)
(a)
The wavelength of the wave.
(a)
![Check Mark](/static/check-mark.png)
Answer to Problem 51CP
The wavelength of the wave is
Explanation of Solution
Given info: The frequency of the wave is
The formula to calculate the wavelength is,
Here,
Substitute
Conclusion:
Therefore, the wavelength of the wave is
(b)
The time period of the wave.
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 51CP
The time period of the wave is
Explanation of Solution
Given info: The frequency of the wave is
The formula to calculate the time period is,
Substitute
Conclusion:
Therefore, the time period of the wave is
(c)
The maximum value of the magnetic field.
(c)
![Check Mark](/static/check-mark.png)
Answer to Problem 51CP
The maximum value of the magnetic field is
Explanation of Solution
Given info: The frequency of the wave is
The formula to calculate the magnitude of the magnetic field is,
Here,
Substitute
Conclusion:
Therefore, the maximum value of the magnetic field is
(d)
The expression for electric field and the magnetic field.
(d)
![Check Mark](/static/check-mark.png)
Answer to Problem 51CP
The expression for electric field is
Explanation of Solution
Given info: The frequency of the wave is
The formula to calculate the angular frequency is,
Here,
Substitute the
The formula to calculate the angular constant is,
Here,
Substitute the
The formula to calculate the electric field is,
Substitute
The electric field is in the same direction of wave propagation.
The formula to calculate the magnetic field is,
Substitute
The direction of propagation of the magnetic field is perpendicular to that of the electric field.
Conclusion:
Therefore, the expression for electric field is
(e)
The average power per unit area the wave carries.
(e)
![Check Mark](/static/check-mark.png)
Answer to Problem 51CP
The average power per unit area the wave carries is
Explanation of Solution
Given info: The frequency of the wave is
The formula to calculate the average power per unit area is,
Here,
Substitute
Conclusion:
Therefore, the average power per unit area the wave carries is
(f)
The average energy density in the
(f)
![Check Mark](/static/check-mark.png)
Answer to Problem 51CP
The average energy density in the radiation is
Explanation of Solution
Given info: The frequency of the wave is
The formula to calculate the average energy density is,
Substitute
Conclusion:
Therefore, the average energy density in the radiation is
(g)
The radiation pressure exerted by the wave.
(g)
![Check Mark](/static/check-mark.png)
Answer to Problem 51CP
The radiation pressure exerted by the wave is
Explanation of Solution
Given info: The frequency of the wave is
The formula to calculate the radiation pressure is,
Substitute
Conclusion:
Therefore, the radiation pressure exerted by the wave is
Want to see more full solutions like this?
Chapter 33 Solutions
Physics for Scientists and Engineers with Modern Physics
- A particular water pipe has a radius of 0.28 meters. If the pipe is completely filled with water, moving with average velocity 0.45 m/s, what is the flow rate of water through the pipe with units of cubic meters of water per second?arrow_forwardWater is flowing through a horizontal pipe with two segments. In one segment, the water flows at a speed v1 = 4.52 m/s. In the second segment the speed of the water is v2 = 2.38 m/s. Based on Bernoulli's Principle, what is the difference in pressure (P2 - P1) between the two segments? Assume that the density of the water is 997 kg/m3 and give your answer as the number of Pascals (i.e. N/m2).arrow_forwardWater from the faucet is supplied to the hose at a rate of 0.00057 m3/s. At what speed (number of meters per second) does the water exit the nozzle if the cross sectional area of the narrow nozzle is 2.1 x 10-6 m2?arrow_forward
- Jason Fruits/Indiana University Research Communications Silver/ silver oxide Zinc zinc/oxidearrow_forwardCar P moves to the west with constant speed v0 along a straight road. Car Q starts from rest at instant 1, and moves to the west with increasing speed. At instant 5, car Q has speed w0 relative to the road (w0 < v0). Instants 1-5 are separated by equal time intervals. At instant 3, cars P and Q are adjacent to one another (i.e., they have the same position). In the reference frame o f the road, at instant 3 i s the speed o f car Q greater than, less than, or equal to the speed of car P? Explain.arrow_forwardCar P moves to the west with constant speed v0 along a straight road. Car Q starts from rest at instant 1, and moves to the west with increasing speed. At instant 5, car Q has speed w0 relative to the road (w0 < v0). Instants 1-5 are separated by equal time intervals.arrow_forward
- Car P moves to the west with constant speed v0 along a straight road. Car Q starts from rest at instant 1, and moves to the west with increasing speed. At instant 5, car Q has speed w0 relative to the road (w0 < v0). Instants 1-5 are separated by equal time intervals. Sketch and label a vector diagram illustrating the Galilean transformation of velocities that relates velocity of car P relative to the road, velocity of car Q relative to road, and velocity of car Q relative to car P at instant 3. In the frame of car P, at instant 3 is car Q moving to the west, moving to the east, or at rest? Explain.arrow_forwardJust 5 and 6 don't mind 7arrow_forwardIn an electron gun, electrons are accelerated through a region with an electric field of magnitude 1.5 × 104 N/C for a distance of 2.5 cm. If the electrons start from rest, how fast are they moving after traversing the gun?arrow_forward
- Please solve and answer this problem correctly please. Thank you!!arrow_forwardPlease solve and answer this problem correctly please. Thank you!!arrow_forwarda) Use the node-voltage method to find v1, v2, and v3 in the circuit in Fig. P4.14. b) How much power does the 40 V voltage source deliver to the circuit? Figure P4.14 302 202 w w + + + 40 V V1 80 Ω 02 ΣΑΩ 28 A V3 + w w 102 202arrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781133939146/9781133939146_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781938168161/9781938168161_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781133104261/9781133104261_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305116399/9781305116399_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337553278/9781337553278_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337553292/9781337553292_smallCoverImage.gif)