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(a)
The wavelength of the wave.
(a)
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Answer to Problem 51CP
The wavelength of the wave is
Explanation of Solution
Given info: The frequency of the wave is
The formula to calculate the wavelength is,
Here,
Substitute
Conclusion:
Therefore, the wavelength of the wave is
(b)
The time period of the wave.
(b)
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Answer to Problem 51CP
The time period of the wave is
Explanation of Solution
Given info: The frequency of the wave is
The formula to calculate the time period is,
Substitute
Conclusion:
Therefore, the time period of the wave is
(c)
The maximum value of the magnetic field.
(c)
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Answer to Problem 51CP
The maximum value of the magnetic field is
Explanation of Solution
Given info: The frequency of the wave is
The formula to calculate the magnitude of the magnetic field is,
Here,
Substitute
Conclusion:
Therefore, the maximum value of the magnetic field is
(d)
The expression for electric field and the magnetic field.
(d)
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Answer to Problem 51CP
The expression for electric field is
Explanation of Solution
Given info: The frequency of the wave is
The formula to calculate the angular frequency is,
Here,
Substitute the
The formula to calculate the angular constant is,
Here,
Substitute the
The formula to calculate the electric field is,
Substitute
The electric field is in the same direction of wave propagation.
The formula to calculate the magnetic field is,
Substitute
The direction of propagation of the magnetic field is perpendicular to that of the electric field.
Conclusion:
Therefore, the expression for electric field is
(e)
The average power per unit area the wave carries.
(e)
![Check Mark](/static/check-mark.png)
Answer to Problem 51CP
The average power per unit area the wave carries is
Explanation of Solution
Given info: The frequency of the wave is
The formula to calculate the average power per unit area is,
Here,
Substitute
Conclusion:
Therefore, the average power per unit area the wave carries is
(f)
The average energy density in the
(f)
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Answer to Problem 51CP
The average energy density in the radiation is
Explanation of Solution
Given info: The frequency of the wave is
The formula to calculate the average energy density is,
Substitute
Conclusion:
Therefore, the average energy density in the radiation is
(g)
The radiation pressure exerted by the wave.
(g)
![Check Mark](/static/check-mark.png)
Answer to Problem 51CP
The radiation pressure exerted by the wave is
Explanation of Solution
Given info: The frequency of the wave is
The formula to calculate the radiation pressure is,
Substitute
Conclusion:
Therefore, the radiation pressure exerted by the wave is
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Chapter 33 Solutions
Physics for Scientists and Engineers with Modern Physics
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
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