a. If you do 12 J of work to push 0.001 C of charge from point A to point B in an electric field, what is the voltage difference between points A and B?
b. When the charge is released, what will be its kinetic energy as it flies back past its starting point A? What principle guides your answer?
(a)
To explain: The voltage difference between points
Explanation of Solution
Work charge particle (q = 0.001 C) moved between points A and B is 12 J .
The voltage difference between A and B,
(b)
To find: The kinetic energy of charged particle and the principle behind it.
Explanation of Solution
Principle is conservation of energy
From the conservation of energy. Total energy of the system remain constant. So decrease in potential energy would increase the kinetic energy. The electric potential energy 12 J will be converted to 12 J of kinetic energy.
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