Explanation Given info: The index of refraction for the transparent solid block is 1.38 . The below figure shows the total internal reflection phenomenon at the vertical face (at point A), Figure (I) θ a is the incident angle of light ray at point B θ b is the refraction angle of light ray at point B ϕ is the incident angle of the light ray at total internal reflection point (at point A ) Expression of Snell’s law for total internal reflection point, sin θ i sin θ r = n air n solid θ i is the incident angle of light ray at point A θ r is the refraction angle of light ray at point A n air is the index of refraction for the air n solid is the index of refraction for the solid For total internal reflection, θ r = 90 ° θ r is the refraction angle of light ray at point A Substitute ϕ for θ i , 90 ° for θ r , 1.0 for n air and 1.38 for n solid to find ϕ , sin ϕ sin 90 ° = 1.0 1.38 sin ϕ = 0.7246 ϕ = sin − 1 ( 0.7246 ) ϕ = 46.439 ° Formula to calculate the refraction angle of light ray at point B , θ b = 90 ° − ϕ θ b is the refraction angle of light ray at point B ϕ is the incident angle of the light ray at total internal reflection point (at point A ) Substitute 46

University Physics with Modern Physics (14th Edition)

14th Edition

ISBN: 9780321973610

Author: Hugh D. Young, Roger A. Freedman

Publisher: PEARSON

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Dispersion of White Light

Snell’s law is a formula that gives a relation between the angle of incidence and angle of refraction and is given as:

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Chapter 33, Problem 33.39P

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The largest angle of incidence θa for which total internal reflection occur at the vertical face (at point A).

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Chapter 33, Problem 33.38P

Chapter 33, Problem 33.40P

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Chapter 33 Solutions

University Physics with Modern Physics (14th Edition)

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The largest angle of incidence θ a for which total internal reflection occur at the vertical face (at point A).

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The largest angle of incidence θa for which total internal reflection occur at the vertical face (at point A).

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Chapter 33 Solutions