Chapter 3.2, Problem 3.9BFP

Interpretation Introduction

Interpretation:

An anabolic steroid contains $\text{C}$ , $\text{H}$ and $\text{O}$ with molar mass $\text{300}\text{.42 g/mol}$ . The combustion of $\text{1}\text{.200 g}$ sample of it produces $\text{3}{\text{.516 g CO}}_{\text{2}}$ and $\text{1}\text{.007 g}$ of ${\text{H}}_{\text{2}}\text{O}$ . The molecular formula of the compound needs to be interpreted.

Concept Introduction:

Empirical formula is the simplest formula of any organic or inorganic compound that represents the simple ratio of all atoms present in the molecule. It can be calculated with the help of the elemental composition of molecule. It is also used to determine the molecular formula of the compound. Certain steps must be used to get the empirical and molecular formula:

• Consider mass % as the mass in grams and calculate moles of the element with the help of molar mass
• Calculate the moles of each element in the least whole number
• Write the number of each atom as a subscript to write the empirical formula
• Use molar mass and mass of empirical formula to determine the molecular formula