Concept explainers
Videos
(a)
Interpretation:
A balanced chemical equation for the reaction between gallium metal and oxygen gas to form solid
Concept introduction:
In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amount of substances in a balanced
Following are the steps to determine the moles of a chemical substance when the moles of another chemical substance present in the chemical reaction are given,
Step 1: Write the names and molecular formulas of the substances involved in the chemical reaction.
Step 2: Write the balanced chemical equation by using
Step 3: Determine the molar ratio from the balanced chemical reaction between the chemical substance whose amount is given and the chemical substance whose amount is to be calculated.
Step 4: Use the molar ratio and the given amount to calculate the unknown amount of the other substance.
(b)
Interpretation:
A balanced chemical equation for the combustion reaction of liquid hexane to form carbon dioxide gas and gaseous water is to be written.
Concept introduction:
In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amount of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.
Following are the steps to determine the moles of a chemical substance when the moles of another chemical substance present in the chemical reaction are given,
Step 1: Write the names and molecular formulas of the substances involved in the chemical reaction.
Step 2: Write the balanced chemical equation by using stoichiometric coefficients.
Step 3: Determine the molar ratio from the balanced chemical reaction between the chemical substance whose amount is given and the chemical substance whose amount is to be calculated.
Step 4: Use the molar ratio and the given amount to calculate the unknown amount of the other substance.
(c)
Interpretation:
A balanced chemical equation for the reaction between calcium chloride and sodium phosphate to form solid calcium phosphate and sodium chloride in the solution is to be written.
Concept introduction:
In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amount of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.
Following are the steps to determine the moles of a chemical substance when the moles of another chemical substance present in the chemical reaction are given,
Step 1: Write the names and molecular formulas of the substances involved in the chemical reaction.
Step 2: Write the balanced chemical equation by using stoichiometric coefficients.
Step 3: Determine the molar ratio from the balanced chemical reaction between the chemical substance whose amount is given and the chemical substance whose amount is to be calculated.
Step 4: Use the molar ratio and the given amount to calculate the unknown amount of the other substance.
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Chapter 3 Solutions
Chemistry The Molecular Nature Of Matter And Change 9th
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- Please correct answer and don't use hand rating and don't use Ai solutionarrow_forward1. For each of the following statements, indicate whether they are true of false. ⚫ the terms primary, secondary and tertiary have different meanings when applied to amines than they do when applied to alcohols. • a tertiary amine is one that is bonded to a tertiary carbon atom (one with three C atoms bonded to it). • simple five-membered heteroaromatic compounds (e.g. pyrrole) are typically more electron rich than benzene. ⚫ simple six-membered heteroaromatic compounds (e.g. pyridine) are typically more electron rich than benzene. • pyrrole is very weakly basic because protonation anywhere on the ring disrupts the aromaticity. • thiophene is more reactive than benzene toward electrophilic aromatic substitution. • pyridine is more reactive than nitrobenzene toward electrophilic aromatic substitution. • the lone pair on the nitrogen atom of pyridine is part of the pi system.arrow_forwardThe following reactions are NOT ordered in the way in which they occur. Reaction 1 PhO-OPh Reaction 2 Ph-O -CH₂ heat 2 *OPh Pho -CH2 Reaction 3 Ph-O ⚫OPh + -CH₂ Reaction 4 Pho Pho + H₂C OPh + CHOPh H₂C -CH₂ Reactions 1 and 3 Reaction 2 O Reaction 3 ○ Reactions 3 and 4 ○ Reactions 1 and 2 Reaction 4 ○ Reaction 1arrow_forward
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