Chapter 32, Problem 32.9QAP

Interpretation Introduction

Interpretation:

The counting rate of sample ${}^{64}Cu$ is 4225cpm. The counting rate of sample after 10.00hr is 2898cpm. The half time of the sample ${}^{64}Cu$ is to be determined.

Concept introduction:

According to first order of kinetics:

$\ln \left(\frac{N}{N_0}\right)=-\lambda t$

Here, N and N_o are final and initial concentrations, $\lambda$ is decay constant and t is time.

$t_{1/2}\left(half-time\right)=\ln \frac{2}{\lambda }$

Or,

$t_{1/2}=\frac{0.693}{\lambda }$

Here, $t_{1/2}$ is half-life time.