Explanation Given Info: The power of laser A is 2.6 W and the diameter of the cylindrical laser beam is 2.6 mm . And uniform intensity distribution over the cross sections, the amplitude of electric field in laser B is 480 V / m . And uniform intensity distribution over the cross sections, The amplitude of the magnetic field in the laser C is 8.7 × 10 − 6 T And uniform intensity distribution over the cross sections, The diameter of the cylindrical beam is 1.8 mm and the force on totally reflected surface is 6.0 × 10 − 8 N . And uniform intensity distribution over the cross sections, The average energy density in the beam is 3.0 × 10 − 7 J / m 3 . And uniform intensity distribution over the cross sections. Formula to calculate the intensity of the beam is, I = P A (I) P is the power of laser A , A is the area of the laser A . Formula to calculate the area of the laser is, A = π d 2 4 d is the diameter of the cylindrical beam. Substitute 2.6 × 10 − 3 m for d , A = π ( 2.6 × 10 − 3 m ) 2 4 = 5.3066 × 10 − 6 m 2 Substitute 5.3066 × 10 − 6 m 2 for A and 2.6 W for P in (I) to find I , I = ( 2.6 W ) 5.3066 × 10 − 6 m 2 = 4.9 × 10 5 W / m 2 Thus, the intensity of the laser A is 4.9 × 10 5 W / m 2 . Formula to calculate the intensity of the electromagnetic wave is, I = 1 2 ε 0 c E max 2 ε 0 is the electric constant, c is the speed of the light in vacuum, E max is the maximum value of the electric field amplitude. Substitute 2.998 × 10 8 m / s for c , 8.854 × 10 − 12 C 2 / N ⋅ m 2 for ε 0 and 480 V / m for E max to find I , I = 1 2 ( 8.854 × 10 − 12 C 2 / N ⋅ m 2 ) ( 2.998 × 10 8 m / s ) ( 480 V / m ) 2 = 310 W / m 2 Thus, the intensity of the laser B is 310 W / m 2 . Formula to calculate the intensity of the electromagnetic wave is, I = 1 2 ε 0 c E max 2 (II) ε 0 is the electric constant, c is the speed of the light in vacuum, E max is the maximum value of the electric field amplitude. Formula to calculate the maximum value of the electric field amplitude as follows, E max = c B max c is the speed of the light in vacuum, B max is the maximum value of the magnetic field amplitude. Substitute c B max for E max in (II), I = 1 2 ε 0 c ( c B max ) 2 = 1 2 ε 0 c 3 B max 2 (III) Substitute 2.998 × 10 8 m / s for c , 8.854 × 10 − 12 C 2 / N ⋅ m 2 for ε 0 and 8.7 × 10 − 6 T for B max in (III) to find I , I = 1 2 ( 8

University Physics with Modern Physics Plus Mastering Physics with eText -- Access Card Package (14th Edition)

14th Edition

ISBN: 9780321982582

Author: Hugh D. Young, Roger A. Freedman

Publisher: PEARSON

See similar textbooks

Question

Chapter 32, Problem 32.48P

To determine

The intensity of the lasers A, B, C, D, E and the rank of the lasers in order of increasing intensity.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 32, Problem 32.47P

Chapter 32, Problem 32.49P

Students have asked these similar questions

A high-energy pulsed laser emits a 1.0ns Long pulse of an average power 2.2x10^11 W. The beam is nearly a cylinder 2.2x10^-3 m in radius. Determine the energy delivered in each pulse and the rms value of the electric field

A 40.0 W incandescent light bulb transforms 19.0% of its energy into visible light; the rest goes largely to non-visible infrared radiation. At what distance from the bulb is the amplitude of the electric field of the visible-light wave 13.1 V/m? Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10 Answer units

You have a parallel plate capacitor made of circular disks which have a radius of 2.00 cm. During a particular interval while the capacitor is charging, the electric field between the plates increases by 760 V/m, and a tiny magnetic field of 6.3 x 10-15 T exists at a point 3.00 cm from the center axis of the capacitor. How much time elapses during this interval? i E S + B

Chapter 32 Solutions

University Physics with Modern Physics Plus Mastering Physics with eText -- Access Card Package (14th Edition)

Ch. 32.1 - (a) Is it possible to have a purely electric wave...Ch. 32.2 - Prob. 32.2TYU Ch. 32.3 - The first of Eqs. (32.17) gives the electric field...Ch. 32.4 - Figure 32.13 shows one wavelength of a sinusoidal...Ch. 32.5 - Prob. 32.5TYU Ch. 32 - By measuring the electric and magnetic fields at a...Ch. 32 - When driving on the upper level of the Bay Bridge,...Ch. 32 - Give several examples of electromagnetic waves...Ch. 32 - Sometimes neon signs located near a powerful radio...Ch. 32 - Is polarization a property of all electromagnetic...

Knowledge Booster

The intensity of the lasers A, B, C, D, E and the rank of the lasers in order of increasing intensity.

Solution Summary: The author calculates the intensity of the lasers A, B, C, D, E, and the rank of them in the order of increasing intensity.

The intensity of the lasers A, B, C, D, E and the rank of the lasers in order of increasing intensity.

Want to see the full answer?

Chapter 32 Solutions