Chapter 3.2, Problem 13P

Find the equilibrium solution, or critical point, of Eqs. $\left(5\right)$ and $\left(6\right)$ of Example $1$.

$\frac{d{u}_1}{dt}=-\left(k_1+k_2\right)u_1+k_2{u}_2+k_1{T}_a$ $-\left(5\right)$

$\frac{d{u}_2}{dt}=\epsilon k_2{u}_1-\epsilon k_2{u}_2$ $-\left(6\right)$