Bundle: Introduction to General, Organic and Biochemistry, 11th + OWLv2, 4 terms (24 months) Printed Access Card
11th Edition
ISBN: 9781305705159
Author: Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 31, Problem 31.84P
Interpretation Introduction
Interpretation:
If the light chain of an immunoglobulin the same as the v region should be explained.
Concept Introduction:
Immunoglobulins which is also recognized as the antibodies, are the glycoprotein molecules formed by the white blood cells or plasma cells. They perform as the major part of the immune response by precisely binding and recognizing to specific antigens, like viruses or bacteria and helping in their destruction.
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
Modify the given carbon skeleton to draw the major product of the following reaction. If a racemic mixture of enantiomers is
expected, draw both enantiomers. Note: you can select a structure and use Copy and Paste to save drawing time.
HBr
کی
CH3
کی
Edit Drawing
Sort the following into the classification for a reaction that is NOT at equilibrium versus a reaction system that has reached equilibrium.
Drag the appropriate items to their respective bins.
View Available Hint(s)
The forward and reverse reactions
proceed at the same rate.
Chemical equilibrium is a dynamic
state.
The ratio of products to reactants is
not stable.
Reset Help
The state of chemical equilibrium will
remain the same unless reactants or
products escape or are introduced into
the system. This will disturb the
equilibrium.
The concentration of products is
increasing, and the concentration of
reactants is decreasing.
The ratio of products to reactants
does not change.
The rate at which products form from
reactants is equal to the rate at which
reactants form from products.
The concentrations of reactants and
products are stable and cease to
change.
The reaction has reached equilibrium.
The rate of the forward reaction is
greater than the rate of the reverse
reaction.
The…
Place the following characteristics into the box for the correct ion. Note that some of the characteristics will not be placed in either bin. Use your periodic table
for assistance.
Link to Periodic Table
Drag the characteristics to their respective bins.
▸ View Available Hint(s)
This anion could form a neutral
compound by forming an ionic bond
with one Ca²+.
Reset
Help
This ion forms ionic bonds with
nonmetals.
This ion has a 1- charge.
This is a polyatomic ion.
The neutral atom from which this ion
is formed is a metal.
The atom from which this ion is
formed gains an electron to become
an ion.
The atom from which this ion is
formed loses an electron to become
an ion.
This ion has a total of 18 electrons.
This ion has a total of 36 electrons.
This ion has covalent bonds and a net
2- charge.
This ion has a 1+ charge.
Potassium ion
Bromide ion
Sulfate ion
Chapter 31 Solutions
Bundle: Introduction to General, Organic and Biochemistry, 11th + OWLv2, 4 terms (24 months) Printed Access Card
Ch. 31 - Give two examples of external innate immunity in...Ch. 31 - Prob. 31.2PCh. 31 - Prob. 31.3PCh. 31 - Prob. 31.4PCh. 31 - Prob. 31.5PCh. 31 - Prob. 31.6PCh. 31 - Prob. 31.7PCh. 31 - 31-8 What are memory cells? What is their...Ch. 31 - Prob. 31.9PCh. 31 - Prob. 31.10P
Ch. 31 - Prob. 31.11PCh. 31 - Prob. 31.12PCh. 31 - Prob. 31.13PCh. 31 - Prob. 31.14PCh. 31 - Prob. 31.15PCh. 31 - Prob. 31.16PCh. 31 - When a foreign substance is injected in a rabbit,...Ch. 31 - Prob. 31.18PCh. 31 - (a) Which immunoglobulin has the highest...Ch. 31 - Chemical Connections 20D states that the antigen...Ch. 31 - Prob. 31.21PCh. 31 - Prob. 31.22PCh. 31 - Prob. 31.23PCh. 31 - Prob. 31.24PCh. 31 - Prob. 31.25PCh. 31 - Prob. 31.26PCh. 31 - What accounts for antibody diversity?Ch. 31 - Prob. 31.28PCh. 31 - Prob. 31.29PCh. 31 - Prob. 31.30PCh. 31 - Prob. 31.31PCh. 31 - Prob. 31.32PCh. 31 - Prob. 31.33PCh. 31 - Prob. 31.34PCh. 31 - Prob. 31.35PCh. 31 - Prob. 31.36PCh. 31 - Prob. 31.37PCh. 31 - Prob. 31.38PCh. 31 - Prob. 31.39PCh. 31 - Prob. 31.40PCh. 31 - Prob. 31.41PCh. 31 - Prob. 31.42PCh. 31 - Prob. 31.43PCh. 31 - Prob. 31.44PCh. 31 - Prob. 31.45PCh. 31 - Prob. 31.46PCh. 31 - Prob. 31.47PCh. 31 - Prob. 31.48PCh. 31 - Prob. 31.49PCh. 31 - Prob. 31.50PCh. 31 - Prob. 31.51PCh. 31 - Prob. 31.52PCh. 31 - Prob. 31.53PCh. 31 - Prob. 31.54PCh. 31 - Prob. 31.55PCh. 31 - Prob. 31.56PCh. 31 - Prob. 31.57PCh. 31 - Prob. 31.58PCh. 31 - Prob. 31.59PCh. 31 - Prob. 31.60PCh. 31 - Prob. 31.61PCh. 31 - Prob. 31.62PCh. 31 - Prob. 31.63PCh. 31 - Prob. 31.64PCh. 31 - Prob. 31.65PCh. 31 - Prob. 31.66PCh. 31 - Prob. 31.67PCh. 31 - Prob. 31.68PCh. 31 - Prob. 31.69PCh. 31 - Prob. 31.70PCh. 31 - Prob. 31.71PCh. 31 - Prob. 31.72PCh. 31 - Prob. 31.73PCh. 31 - Prob. 31.74PCh. 31 - Prob. 31.75PCh. 31 - Prob. 31.76PCh. 31 - Prob. 31.77PCh. 31 - Prob. 31.78PCh. 31 - Prob. 31.79PCh. 31 - Prob. 31.80PCh. 31 - Prob. 31.81PCh. 31 - Prob. 31.82PCh. 31 - Prob. 31.83PCh. 31 - Prob. 31.84PCh. 31 - Prob. 31.85PCh. 31 - Prob. 31.86P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- U Consider the following graph containing line plots for the moles of Product 1 versus time (minutes) and the moles of Product 2 versus time in minutes. Choose all of the key terms/phrases that describe the plots on this graph. Check all that apply. ▸ View Available Hint(s) Slope is zero. More of Product 1 is obtained in 12 minutes. Slope has units of moles per minute. plot of minutes versus moles positive relationship between moles and minutes negative relationship between moles and minutes Slope has units of minutes per moles. More of Product 2 is obtained in 12 minutes. can be described using equation y = mx + b plot of moles versus minutes y-intercept is at (12,10). y-intercept is at the origin. Product Amount (moles) Product 1 B (12,10) Product 2 E 1 Time (minutes) A (12,5)arrow_forwardSolve for x, where M is molar and s is seconds. x = (9.0 × 10³ M−². s¯¹) (0.26 M)³ Enter the answer. Include units. Use the exponent key above the answer box to indicate any exponent on your units. ▸ View Available Hint(s) ΜΑ 0 ? Units Valuearrow_forwardLearning Goal: This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this: 35 Cl 17 In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is: It is also correct to write symbols by leaving off the atomic number, as in the following form: atomic number mass number Symbol 35 Cl or mass number Symbol This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written. Watch this video to review the format for written symbols. In the following table each column…arrow_forward
- need help please and thanks dont understand only need help with C-F Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal…arrow_forwardneed help please and thanks dont understand only need help with C-F Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal…arrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- need help please and thanks dont understand a-b Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal energy Divide the…arrow_forwardPlease correct answer and don't used hand raitingarrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- Can you tell me if my answers are correctarrow_forwardBunsenite (NiO) crystallizes like common salt (NaCl), with a lattice parameter a = 4.177 Å. A sample of this mineral that has Schottky defects that are not supposed to decrease the volume of the material has a density of 6.67 g/cm3. What percentage of NiO molecules is missing? (Data: atomic weight of Ni: 58.7; atomic weight of O: 16).arrow_forwardA sample of aluminum (face-centered cubic - FCC) has a density of 2.695 mg/m3 and a lattice parameter of 4.04958 Å. Calculate the fraction of vacancies in the structure. (Atomic weight of aluminum: 26.981).arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning
Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,
Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning
World of ChemistryChemistryISBN:9780618562763Author:Steven S. ZumdahlPublisher:Houghton Mifflin College Div
Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
General, Organic, and Biological Chemistry
Chemistry
ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:Cengage Learning
Organic And Biological Chemistry
Chemistry
ISBN:9781305081079
Author:STOKER, H. Stephen (howard Stephen)
Publisher:Cengage Learning,
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Cengage Learning
World of Chemistry, 3rd edition
Chemistry
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Brooks / Cole / Cengage Learning
World of Chemistry
Chemistry
ISBN:9780618562763
Author:Steven S. Zumdahl
Publisher:Houghton Mifflin College Div
Chemistry for Today: General, Organic, and Bioche...
Chemistry
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Cengage Learning
DIGESTER-35 | VITAMINS AND THEIR RELATED COENZYMES| GPAT | NIPER | PHARMACIST| DI; Author: GPAT DISCUSSION CENTER;https://www.youtube.com/watch?v=CGrdNYmho0s;License: Standard YouTube License, CC-BY