ORGANIC CHEMISTRY
5th Edition
ISBN: 9781259977596
Author: SMITH
Publisher: MCG
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Chapter 31, Problem 31.29P
An isoprene unit can be thought of as having a head and a tail. The “head” of the isoprene unit is located at the end of the chain nearest the branch point, and the “tail” is located at the end of the carbon chain farthest from the branch point. Most isoprene units are connected together in a “head-to-tail” fashion, as illustrated. For both lycopene (Problem 31.26), and squalene (Figure 31.9), decide which isoprene units are connected in a head-to-tail fashion and which are not.
These two isoprene units are
connected in head-tail fashion.
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An isoprene unit can be thought of as having a head and a tail. The "head" of the isoprene unit is located at the end of the chain
nearest the branch point, and the "tail" is located at the end of the carbon chain farthest from the branch point. Most isoprene
units are connected together in a "head-to-tail" fashion, as illustrated. For both lycopene (Problem 30.28), and squalene (Figure
30.9), decide which isoprene units are connected in a head-to-tail fashion and which are not.
head tail
tail head
These two isoprene units are
connected in a head-to-tail fashion.
Show the structure of the furfural products/derivatives of the given compounds which were subjected to Seliwanoff's Test.
compounds: sucrose, fructose, and glucose
264&OpenVellumHMAC-ab644d9786730f4650f72638a7bd0c5b#10001
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amylose and cellulose
Match the words in the left column to the appropriate blanks in the sentences on the right.
a(16)
B(14)
a(12)
glucose
a(14)
8(16)
a(12)
fructose
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a(12)
B(16)
a(16)
cellulose and chitin
Match the words in the left column to the appropriate blanks in the sentences on the right.
glucose
-tose also called - Search
a(14)
fructose
8(14)
B(12)
x | +
Both are linear polysaccharides composed entirely of
linkages are
but in cellulose, they are
Both are linear polysaccharides with
2
DELL
and chitin contains N-acetylglucosamine.
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In amylose, the glycosidic
glycosidic bonds. Cellulose contains
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Chapter 31 Solutions
ORGANIC CHEMISTRY
Ch. 31 - Problem 31.1
One component of jojoba oil is a wax...Ch. 31 - Problem 31.2
How would you expect the melting...Ch. 31 - Problem 31.3
Draw the products formed when...Ch. 31 - Problem 31.4
The main fatty acid component of the...Ch. 31 - Prob. 31.5PCh. 31 - Problem 31.6
Draw the structure of a lecithin...Ch. 31 - Prob. 31.7PCh. 31 - Problem 31.8
Why are phospholipids, but not...Ch. 31 - Problem 31.9
Explain why regularly ingesting a...Ch. 31 - Problem 31.10
Locate the isoprene units in each...
Ch. 31 - Problem 31.11
Locate the isoprene units in...Ch. 31 - Problem 31.12
Write a stepwise mechanism for the...Ch. 31 - Prob. 31.13PCh. 31 - Prob. 31.14PCh. 31 - Prob. 31.15PCh. 31 - Prob. 31.16PCh. 31 - 31.17 Locate the isoprene units in each...Ch. 31 - Prob. 31.18PCh. 31 - Prob. 31.19PCh. 31 - Prob. 31.20PCh. 31 - Prob. 31.21PCh. 31 - 31.22 What is the structure of an optically...Ch. 31 - Prob. 31.23PCh. 31 - 31.24 Draw the structure of the following...Ch. 31 - Prob. 31.25PCh. 31 - Locate the isoprene units in each compound. a. e....Ch. 31 - 31.27 Classify each terpene and terpenoid in...Ch. 31 - 31.38 Draw the products formed when cholesterol is...Ch. 31 - 31.29 An isoprene unit can be thought of as having...Ch. 31 - 31.30 Draw a stepwise mechanism for the conversion...Ch. 31 - Prob. 31.31PCh. 31 - Prob. 31.32PCh. 31 - Draw three-dimensional structures f or each...Ch. 31 - Prob. 31.34PCh. 31 - Prob. 31.35PCh. 31 - Prob. 31.36PCh. 31 - Prob. 31.37PCh. 31 - 31.38 Draw the products formed when cholesterol is...Ch. 31 - 31.39 Draw a stepwise mechanism for the following...Ch. 31 - 31.40 Draw a stepwise mechanism for the following...Ch. 31 - Prob. 31.41P
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- The final four questions will require you to determine whether the compound in question will partition into the organic or aqueous phase. Which layer will phenylalanine partition into? Note: look up "zwitterions" water diethyl etherarrow_forwardWhat is the structure of Cellulose in Open Structure(Fischer) and in Closed Structure (Haworth)?arrow_forwardAnswer I.arrow_forward
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- Monosaccharides are cyclic hemiacetals that can react with alcohols to form acetals. The bond between the anomeric carbon atom of the monosaccharide and the oxygen atom of the -OR group is called a glycosidic bond. The name of the linkage contains the designation alpha (a) or beta (B) (from the anomeric carbon in the glycosidic bond) and the carbon numbers for the carbons from the two sugars. For this example, the linkage is an a-1,4 glycosidic bond. Н НО HO اب تاب است H OH H OH -OH Н Н OH H + OH HO a anomer CH₂OH H Н H О OH H2C OH Н H Classify the glycosidic linkage in the disaccharide. Н OH Н H OH OH OH - HO Н H HO OH OH Н CH₂OH H -OH H OH он H H -OH Н OH an a glycosidic bond Н OH + H2O о о о о В-1,6 a-1,6 a-1,1 B-1,5 I DON'T KNOW YET submitarrow_forwardWhich statement about saccharides is correct? (A). Alpha anomers are more common than beta anoomers. (B). Two monosaccharides can form a disaccharide and oxygen. (C). Polysaccharides with alpha or beta glycosidic linkages have the different properties. (D). Disaccharides can be cyclic or acyclic.arrow_forwardExplain why lactose and maltose differs from sucrose in its chemical activity with Fehling’s, Benedict’s and using Seliwanoff’s reagents?arrow_forward
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