To show that it is not possible for a single photon to be produced by the collision of one electron and positron with equal opposite speed of less magnitude.

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Answer 1

Question

Chapter 30, Problem 41P

(a)

To determine

To show that it is not possible for a single photon to be produced by the collision of one electron and positron with equal opposite speed of less magnitude.

(b)

To determine

To show that if two photons are created by the annihilation of a electron and positron with equal and opposite velocity before collision, the two photons must travel in the opposite direction and their energy is same.

(c)

To determine

The wavelength of the two photons and which part of electromagnetic spectrum this photon belong.

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Students have asked these similar questions

Is it possible that some parts of the universe contain antimatter whose atoms have nuclei made of antiprotons and antineutrons, surrounded by positrons? How could we detect this condition without actually going there? Can we detect these antiatoms by identifying the light they emit as composed of antiphotons? Explain. What problems might arise if we actually did go there?

Suppose you were to try to create a proton-antiproton pair by annihilation of two very high-energy gamma rays of the same wavelength heading toward each other. The proton and the anti-proton have the same masses, but opposite charges. What would be the minimum energy needed for each photon? (e = 1.60 × 10-19 C, m proton = 1.67 × 10-27 kg, c = 3.00 × 108 m/s) 939 MeV O1.022 MeV O 12.2 MeV O 1880 MeV

(a) A particle and its antiparticle are at rest relative to an observer and annihilate (completely destroying both masses), creating two γ rays of equal energy. What is the characteristic γ -ray energy you would look for if searching for evidence of proton-antiproton annihilation? (The fact thatsuch radiation is rarely observed is evidence that there is very little antimatter in the universe.) (b) How does this compare with the 0.511-MeV energy associated with electron-positron annihilation?

Answer 2

Question

Chapter 30, Problem 41P

(a)

To determine

To show that it is not possible for a single photon to be produced by the collision of one electron and positron with equal opposite speed of less magnitude.

(b)

To determine

To show that if two photons are created by the annihilation of a electron and positron with equal and opposite velocity before collision, the two photons must travel in the opposite direction and their energy is same.

(c)

To determine

The wavelength of the two photons and which part of electromagnetic spectrum this photon belong.

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Answer 3

Question

Chapter 30, Problem 41P

(a)

To determine

To show that it is not possible for a single photon to be produced by the collision of one electron and positron with equal opposite speed of less magnitude.

(b)

To determine

To show that if two photons are created by the annihilation of a electron and positron with equal and opposite velocity before collision, the two photons must travel in the opposite direction and their energy is same.

(c)

To determine

The wavelength of the two photons and which part of electromagnetic spectrum this photon belong.

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Answer 4

Question

Chapter 30, Problem 41P

(a)

To determine

To show that it is not possible for a single photon to be produced by the collision of one electron and positron with equal opposite speed of less magnitude.

(b)

To determine

To show that if two photons are created by the annihilation of a electron and positron with equal and opposite velocity before collision, the two photons must travel in the opposite direction and their energy is same.

(c)

To determine

The wavelength of the two photons and which part of electromagnetic spectrum this photon belong.

Expert Solution & Answer

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Answer 5

Chapter 30, Problem 41P

(a)

To determine

To show that it is not possible for a single photon to be produced by the collision of one electron and positron with equal opposite speed of less magnitude.

(b)

To determine

To show that if two photons are created by the annihilation of a electron and positron with equal and opposite velocity before collision, the two photons must travel in the opposite direction and their energy is same.

(c)

To determine

The wavelength of the two photons and which part of electromagnetic spectrum this photon belong.

Answer 6

Chapter 30, Problem 41P

(a)

To determine

To show that it is not possible for a single photon to be produced by the collision of one electron and positron with equal opposite speed of less magnitude.

Answer 7

Chapter 30, Problem 41P

(a)

To determine

To show that it is not possible for a single photon to be produced by the collision of one electron and positron with equal opposite speed of less magnitude.

Answer 8

(b)

To determine

To show that if two photons are created by the annihilation of a electron and positron with equal and opposite velocity before collision, the two photons must travel in the opposite direction and their energy is same.

Answer 9

(b)

To determine

To show that if two photons are created by the annihilation of a electron and positron with equal and opposite velocity before collision, the two photons must travel in the opposite direction and their energy is same.

Answer 10

(c)

To determine

The wavelength of the two photons and which part of electromagnetic spectrum this photon belong.

Answer 11

(c)

To determine

The wavelength of the two photons and which part of electromagnetic spectrum this photon belong.

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

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Answer 15

Ch. 30 - Prob. 1CQ Ch. 30 - Prob. 2CQ Ch. 30 - True or false? During one half-life, the mass of a...Ch. 30 - Changing the temperature of atoms affects their...Ch. 30 - Prob. 5CQ Ch. 30 - Prob. 6CQ Ch. 30 - Prob. 7CQ Ch. 30 - Prob. 8CQ Ch. 30 - Prob. 9CQ Ch. 30 - Prob. 10CQ

To show that it is not possible for a single photon to be produced by the collision of one electron and positron with equal opposite speed of less magnitude.

Solution Summary: The author explains that it is not possible for a single photon to be produced by the collision of one electron and positron with equal opposite speed of less magnitude.

Concept explainers

To show that it is not possible for a single photon to be produced by the collision of one electron and positron with equal opposite speed of less magnitude.

To show that if two photons are created by the annihilation of a electron and positron with equal and opposite velocity before collision, the two photons must travel in the opposite direction and their energy is same.

The wavelength of the two photons and which part of electromagnetic spectrum this photon belong.

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Chapter 30 Solutions