College Physics (10th Edition)
10th Edition
ISBN: 9780321902788
Author: Hugh D. Young, Philip W. Adams, Raymond Joseph Chastain
Publisher: PEARSON
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Question
Chapter 30, Problem 1CQ
To determine
The way by which the isotopes can be differentiate.
Expert Solution & Answer
Answer to Problem 1CQ
Though the isotopes are having same chemical properties but the isotopes are having different number of neutrons.
Explanation of Solution
Isotopes of a particular element are having same number of protons. Different
But the mass number is different for the isotopes. This is because of the number of neutrons. The neutron number for the different isotopes of a particular material is different.
Thus, though the isotopes are having same chemical properties but the isotopes are having different number of neurons.
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Chapter 30 Solutions
College Physics (10th Edition)
Ch. 30 - Prob. 1CQCh. 30 - Prob. 2CQCh. 30 - True or false? During one half-life, the mass of a...Ch. 30 - Changing the temperature of atoms affects their...Ch. 30 - Prob. 5CQCh. 30 - Prob. 6CQCh. 30 - Prob. 7CQCh. 30 - Prob. 8CQCh. 30 - Prob. 9CQCh. 30 - Prob. 10CQ
Ch. 30 - Prob. 11CQCh. 30 - Prob. 12CQCh. 30 - Prob. 3MCPCh. 30 - Prob. 4MCPCh. 30 - Prob. 5MCPCh. 30 - Prob. 6MCPCh. 30 - Prob. 7MCPCh. 30 - Prob. 8MCPCh. 30 - Prob. 9MCPCh. 30 - Prob. 10MCPCh. 30 - Prob. 11MCPCh. 30 - Prob. 12MCPCh. 30 - Prob. 1PCh. 30 - Prob. 2PCh. 30 - Prob. 3PCh. 30 - Prob. 4PCh. 30 - Prob. 5PCh. 30 - Prob. 6PCh. 30 - Prob. 7PCh. 30 - Prob. 8PCh. 30 - Prob. 9PCh. 30 - Prob. 10PCh. 30 - Prob. 11PCh. 30 - Prob. 12PCh. 30 - Prob. 13PCh. 30 - Prob. 14PCh. 30 - Calcium-47 is a emitter with a half-life of 4.5...Ch. 30 - Prob. 16PCh. 30 - Prob. 17PCh. 30 - Prob. 18PCh. 30 - Prob. 19PCh. 30 - Prob. 20PCh. 30 - Prob. 21PCh. 30 - Prob. 22PCh. 30 - Prob. 23PCh. 30 - Prob. 24PCh. 30 - Prob. 25PCh. 30 - Prob. 26PCh. 30 - Prob. 27PCh. 30 - Prob. 28PCh. 30 - Prob. 29PCh. 30 - Prob. 30PCh. 30 - Prob. 31PCh. 30 - Prob. 32PCh. 30 - Prob. 33PCh. 30 - Prob. 34PCh. 30 - Prob. 35PCh. 30 - Prob. 36PCh. 30 - Prob. 37PCh. 30 - Prob. 38PCh. 30 - Prob. 39PCh. 30 - Prob. 40PCh. 30 - Prob. 41PCh. 30 - Prob. 42PCh. 30 - Prob. 43PCh. 30 - Prob. 44PCh. 30 - Prob. 45PCh. 30 - Prob. 46PCh. 30 - Prob. 47PCh. 30 - Prob. 48PCh. 30 - Prob. 49PCh. 30 - The results of activity measurements on a...Ch. 30 - Prob. 51GPCh. 30 - Prob. 52GPCh. 30 - Prob. 53GPCh. 30 - Prob. 54GPCh. 30 - Prob. 55GPCh. 30 - Prob. 56GPCh. 30 - Prob. 57GPCh. 30 - Prob. 58GPCh. 30 - Prob. 59GPCh. 30 - The atomic mass of 2056Co is 55.934939 u, and the...Ch. 30 - Prob. 61GPCh. 30 - Prob. 62GPCh. 30 - Prob. 63GPCh. 30 - Prob. 64PPCh. 30 - Prob. 65PPCh. 30 - Prob. 66PPCh. 30 - Prob. 67PPCh. 30 - Prob. 68PPCh. 30 - Prob. 69PPCh. 30 - Prob. 70PPCh. 30 - Prob. 71PP
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- (a) Calculate BE/A for 235U, the rarer of the two most common uranium isotopes. (b) Calculate BE/A for 238U. (Most of uranium is 238U.) Note that 238U has even numbers at both protons and neutrons. Is the BE/A of 238U significantly different from that of 235U?arrow_forwardSilver has two stable isotopes. The nucleus, 47107Ag , has atomic mass 106.905095 g/mol with an abundance of 51.83% ; whereas 47107Aghas atomic mass 108.904754 g/mol with an abundance of 48.17% . Find the atomic mass of the element silver.arrow_forwardData from the appendices and the periodic table may be needed for these problems. Unreasonable Results (a) Repeat Exercise 31.57 but include the 0.0055% natural abundance of 234U with its 2.45105y halflife. (b) What is unreasonable about this result? (c) What assumption is responsible? (d) Where does the 234U come from if it is not primordial?arrow_forward
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- Why is the number of neutrons greater than the number of protons in stable nuclei that have an A greater than about 40? Why is this effect more pronounced for the heaviest nuclei?arrow_forward2H is a loosely hound isotope of hydrogen. Called deuterium or heavy hydrogen, it is stable but relatively rareit is 0.015% of natural hydrogen. Note that deuterium has Z = N, which should tend to make it more tightly bound, but both are odd numbers. Calculate BE/A, the binding energy per nucleon, for 2H and compare it with the approximate value obtained from line graph in Figure 31.27.arrow_forwardSuppose you have a pure radioactive material with a half-life of T1/2. You begin with N0 undecayed nuclei of the material at t = 0. At t=12T1/2, how many of the nuclei have decayed? (a) 14N0 (b) 12N0(C) 34N0 (d) 0.707N0 (e) 0.293N0arrow_forward
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