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Chapter 30, Problem 30.30P
An isoprene unit can be thought of as having a head and a tail. The “head” of the isoprene unit is located at the end of the chain nearest the branch point, and the “tail” is located at the end of the carbon chain farthest from the branch point. Most isoprene units are connected together in a “head-to-tail” fashion, as illustrated. For both lycopene (Problem 31.26), and squalene (Figure 31.9), decide which isoprene units are connected in a head-to-tail fashion and which are not.
These two isoprene units are
connected in head-tail fashion.
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An isoprene unit can be thought of as having a head and a tail. The "head" of the isoprene unit is located at the end of the chain
nearest the branch point, and the "tail" is located at the end of the carbon chain farthest from the branch point. Most isoprene
units are connected together in a "head-to-tail" fashion, as illustrated. For both lycopene (Problem 30.28), and squalene (Figure
30.9), decide which isoprene units are connected in a head-to-tail fashion and which are not.
head tail
tail head
These two isoprene units are
connected in a head-to-tail fashion.
Show the structure of the furfural products/derivatives of the given compounds which were subjected to Seliwanoff's Test.
compounds: sucrose, fructose, and glucose
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amylose and cellulose
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B(14)
a(12)
glucose
a(14)
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cellulose and chitin
Match the words in the left column to the appropriate blanks in the sentences on the right.
glucose
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a(14)
fructose
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Both are linear polysaccharides composed entirely of
linkages are
but in cellulose, they are
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2
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In amylose, the glycosidic
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Chapter 30 Solutions
Organic Chemistry-Package(Custom)
Ch. 30 - Problem 31.1
One component of jojoba oil is a wax...Ch. 30 - Prob. 30.2PCh. 30 - Problem 31.3
Draw the products formed when...Ch. 30 - Problem 31.4
The main fatty acid component of the...Ch. 30 - Prob. 30.5PCh. 30 - Problem 31.6
Draw the structure of a lecithin...Ch. 30 - Prob. 30.7PCh. 30 - Problem 31.8
Why are phospholipids, but not...Ch. 30 - Problem 31.9
Explain why regularly ingesting a...Ch. 30 - Prob. 30.10P
Ch. 30 - Problem 31.10
Locate the isoprene units in each...Ch. 30 - Prob. 30.12PCh. 30 - Problem 31.11
Locate the isoprene units in...Ch. 30 - Problem 31.12
Write a stepwise mechanism for the...Ch. 30 - Prob. 30.15PCh. 30 - Prob. 30.16PCh. 30 - Prob. 30.17PCh. 30 - Prob. 30.18PCh. 30 - 31.17 Locate the isoprene units in each...Ch. 30 - Prob. 30.20PCh. 30 - Prob. 30.21PCh. 30 - Prob. 30.22PCh. 30 - Prob. 30.23PCh. 30 - 31.22 What is the structure of an optically...Ch. 30 - Prob. 30.25PCh. 30 - 31.24 Draw the structure of the following...Ch. 30 - Prob. 30.27PCh. 30 - Locate the isoprene units in each compound. a. e....Ch. 30 - Classify each terpene and terpenoid in Problem...Ch. 30 - 31.29 An isoprene unit can be thought of as having...Ch. 30 - 31.30 Draw a stepwise mechanism for the conversion...Ch. 30 - Prob. 30.32PCh. 30 - Prob. 30.33PCh. 30 - Draw three-dimensional structures f or each...Ch. 30 - Prob. 30.35PCh. 30 - Prob. 30.36PCh. 30 - Prob. 30.37PCh. 30 - 31.38 Draw the products formed when cholesterol is...Ch. 30 - 31.39 Draw a stepwise mechanism for the following...Ch. 30 - 31.40 Draw a stepwise mechanism for the following...Ch. 30 - Prob. 30.41P
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- In general, the starch hydrolysis reaction can be written as (C6H10O5)n + H2O -> (C6H10O5)n-1 + C6H12O6, where one glucose is produced for every water added. Because of the addition of water, the mass of the glucose monomer increases during hydrolysis from approximately 162g/mol in the starch polymer to 180g/mol as free sugar. The glucose, in turn is converted to ethanol by the yeast, Saccharomyces cerevisiae, according to the reaction, C6H12O6 -> 2 CO2 + 2 C2H5OH. The starch in 25kg (~1 bushel) of corn is hydrolyzed and in the process 1.8kg of water (H2O) is consumed. How many moles of glucose (C6H12O6) would you expect to be produced? If the glucose from the above hydrolysis is fermented, how many moles of ethanol (C2H5OH) would result? How many grams?arrow_forward43. Specify expressions specific to panaxosides. I. taken from ginseng II. there are glucose and arabinose monosaccharides in this compound III. taken from Japanese angelica-tree IV. tetratcyclic triterpen saponins V. spirostanol type glycoside VI. dimer structure VII. biglycosides VIII. dammaran group IX. differ for number of hydroxyl groups X. furostanol type glycoside A) II; VI; VII; IX; X B) III; V; VIII C) I; IV; VIII; IX D) I; VIII; IX E) I; III; V; VII; VIII; Xarrow_forwardShow the structure of the furfural products/derivatives of the given compounds which were subjected to Molisch Test. compounds: starch, sucrose, and glucosearrow_forward
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