DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
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Chapter 30, Problem 24RQ
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The definition of undercut.
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for this 4 figuredarw the Kinematic Diagram:DoF:F=Type/Name ofmechanismEvolution:
Two channels and two plates are used to formthe column section shown. For b = 200 mm,determine the moments of inertia and theradii of gyration of the combined section withrespect to the centroidal x and y axes.For the section of problem, determine thefirst moment of the upper plate about thecentroidal x-axis
Determine by direct integration the moment of inertia of theshaded area at right with respect to the x axis shown.
Determine by direct integration the moment of inertia of theshaded area of the figure with respect to the y axis shown.
Chapter 30 Solutions
DeGarmo's Materials and Processes in Manufacturing
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Ch. 30 - How is ECM related to chemical machining?Ch. 30 - What effect does work material hardness have on...Ch. 30 - What is the principal cause of tool wear in ECM?Ch. 30 - Would electrochemical grinding be a suitable...Ch. 30 - Upon what factors does the metal removal rate...Ch. 30 - Why is the tool insulated in the ECM schematic?Ch. 30 - What is the nature of the surface obtained by...Ch. 30 - What is the principal advantage of using a moving...Ch. 30 - What effect would increasing the voltage have on...Ch. 30 - If a metal part is quite brittle and the part will...Ch. 30 - If you had to make several holes in a large number...Ch. 30 - Prob. 22RQCh. 30 - Explain (using a little physics and metallurgy)...Ch. 30 - Prob. 24RQCh. 30 - What are some possible defects that can result...Ch. 30 - What are some other uses for the laser other than...Ch. 30 - How does the laser produce coherent light...Ch. 30 - What is ablation?Ch. 30 - What is an excimer?Ch. 30 - In Figure 30.16, what is the protective tape...Ch. 30 - Why is the EBM process done in a vacuum?Ch. 30 - What is the major problem with the redesigned cap...
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- (read image) Answer Providedarrow_forwardThis is part B Part A's question and answer was find moment of inertia (Ix = 3.90×10^5) and radius of gyration (kx = 21.861) Determine the centroid ( x & y ) of the I-section, Calculate the moment of inertia of the section about itscentroidal x & y axes. How or why is this result different fromthe result of a previous problem?arrow_forwardDetermine by direct integration the moment of inertia of theshaded area of figure with respect to the y axis shownarrow_forward
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