DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
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Textbook Question
Chapter 30, Problem 15RQ
Upon what factors does the metal removal rate depend in ECM?
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The frontal working area of the electrode in an ECM operation is 2000 mm?. The applied current is 2000 amps
and the voltage is 12 volts. The material being cut is nickel (valence = 2, CN; =3.42x10-2mm2/A-s). (a) If the
process is 90% efficient, determine the cutting rate into the workpart. (b) If the resistivity of the electrolyte is
160 ohm – mm, determine the working gap.
Tool feed
Tool holder and
feed mechanism
Formed tool (cathode).
Electrolyte flow
-Insulation
Electrolyte
Work (anode)
feed
mm/min
gap
micrometers
The frontal working area of the electrode in an Electrochemical Machining (ECM)
operation is 1000 mm. The applied current is 900 amps and the voltage is 12 volts.
The resistivity of the electi olyte is 140 Q-mm. The material being cut has a valency
of 4 and specific removal rate of 0.0342 mm /A-s. If the process efficiency is 90%,
determine the material remova! rate (MRR) and inter-electrode gap after 30 minutes
of machining when the resistivity of the electrolyte has dropped to 75% of its
original value.
Explain the differences between active and passive recovery methods.
Chapter 30 Solutions
DeGarmo's Materials and Processes in Manufacturing
Ch. 30 - How do the MRRs for most NTM processes compare to...Ch. 30 - What are the steps in chemical machining using...Ch. 30 - In chemical machining, should the etchant be...Ch. 30 - What are the advantages of chemical blanking over...Ch. 30 - How are multiple depths of cut (steps) produced by...Ch. 30 - Would it be feasible to produce a groove 2 mm wide...Ch. 30 - A drawing calls for making a groove 23 mm wide and...Ch. 30 - Could an ordinary steel weldment be chemically...Ch. 30 - How could you produce a tapered section by...Ch. 30 - What is the principal application of...
Ch. 30 - How is ECM related to chemical machining?Ch. 30 - What effect does work material hardness have on...Ch. 30 - What is the principal cause of tool wear in ECM?Ch. 30 - Would electrochemical grinding be a suitable...Ch. 30 - Upon what factors does the metal removal rate...Ch. 30 - Why is the tool insulated in the ECM schematic?Ch. 30 - What is the nature of the surface obtained by...Ch. 30 - What is the principal advantage of using a moving...Ch. 30 - What effect would increasing the voltage have on...Ch. 30 - If a metal part is quite brittle and the part will...Ch. 30 - If you had to make several holes in a large number...Ch. 30 - Prob. 22RQCh. 30 - Explain (using a little physics and metallurgy)...Ch. 30 - Prob. 24RQCh. 30 - What are some possible defects that can result...Ch. 30 - What are some other uses for the laser other than...Ch. 30 - How does the laser produce coherent light...Ch. 30 - What is ablation?Ch. 30 - What is an excimer?Ch. 30 - In Figure 30.16, what is the protective tape...Ch. 30 - Why is the EBM process done in a vacuum?Ch. 30 - What is the major problem with the redesigned cap...
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- What is a CHMSL?arrow_forward(Electrochemical Machining) An ECM operation is used to cut a hole into a plate of stainless steel that is 10 mm thick. The hole has a rectangular cross section, 15 mm by 25 mm. The operation is accomplished at a current = 1300 amps. Efficiency is 97%. Determine the feed rate and time to cut through the plate. The specific removal rate C for stainless steel = 2.46 × 10-2 mm3/A-s. R - V = CIt I = V = gr A V At fr EA gr C(EAt) gr fr CI A CE gr Typical values of specific removal rate C' for selected work materials in electrochemical machining. Compiled from data in [11]. Specific Removal Rate C Materialª mm³/amp-sec (in³/amp-min) Materialª Aluminum (3) Copper (1) Iron (2) Nickel (2) 3.44 x 10-2 7.35 × 10-2 3.69 × 10-2 (1.26 × 10-4) (2.69 x 10-4) (1.35 × 10-4) 3.42 × 10-2 (1.25 × 10-4) X Low alloy steel High alloy steel Stainless steel Titanium (4) Specific Removal Rate C mm³/amp-sec (in³/amp-min) (1.1 × 10-4) 3.0 x 10-2 2.73 × 10-2 2.46 × 10-2 (1.0 × 10-4) (0.9 × 10-4) 2.73 x 10-2 (1.0 ×…arrow_forwardi need the answer quicklyarrow_forward
- Why should copper-phosphorus not be used on fittings with ferrous substrates?arrow_forwardA workpiece (dimensions 100 X 100 X 2 mm) with a 10 mm bore is completely immersed in the anodizing bath and anodized. An anodized layer thickness of 60 µm is detected using a microscope.a) What is the new diameter of the hole?b) What amperage is recommended for the electrolysis of the workpiece?c) At which point is oxygen released (at the anode or cathode)arrow_forwardI need answer within 20 minutes please please with my best wishesarrow_forward
- How has the material removal process evolved over time؟arrow_forwardWhat is one method of preventing damage to work clamped in a vise?arrow_forwardMain characteristic when cutting Non-ferrous materials ISO N is: O Machining at higher speeds creates abrasive wear Non-ferrous materials are sticky and need sharp cutting edges Machining creates high cutting forces, built-up edge, heat and deformation hardeningarrow_forward
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