Chapter 3, Problem 97QRT

Interpretation Introduction

Interpretation:

When $\text{36}\text{.04 mL of 0}\text{.509 M NaOH}$ is required to react with acid, the molar mass of acid has to be calculated.

  ${\text{H}}_{\text{2}}\text{A(aq) + 2 NaOH(aq) }\to {\text{ Na}}_{\text{2}}{\text{A(aq) + 2 H}}_{\text{2}}\text{O(l) }$

Concept introduction:

Molar mass of a substance is the mass in grams of one mole of a substance.

  $No.ofmoles=\frac{Mass\times 1mol}{Molarmass}$