(a) Repeat the problem two problems prior, but for the second leg you walk 20.0 m in a direction 40.0° north of east (which is equivalent to subtracting B from A that is, to finding R ' = A − B ). (b) Repeat the problem two problems prior, but now you first walk 20.0 m in a direction 40.0° south of west and then 12.0 m in a direction 20.0° east of south (which is equivalent to subtracting A from B that is, to finding R ' ' = B − A = − R ' ). Show that this is the case.
(a) Repeat the problem two problems prior, but for the second leg you walk 20.0 m in a direction 40.0° north of east (which is equivalent to subtracting B from A that is, to finding R ' = A − B ). (b) Repeat the problem two problems prior, but now you first walk 20.0 m in a direction 40.0° south of west and then 12.0 m in a direction 20.0° east of south (which is equivalent to subtracting A from B that is, to finding R ' ' = B − A = − R ' ). Show that this is the case.
(a) Repeat the problem two problems prior, but for the second leg you walk 20.0 m in a direction 40.0° north of east (which is equivalent to subtracting B from A that is, to finding
R
'
=
A
−
B
). (b) Repeat the problem two problems prior, but now you first walk 20.0 m in a direction 40.0° south of west and then 12.0 m in a direction 20.0° east of south (which is equivalent to subtracting A from B that is, to finding
R
'
'
=
B
−
A
=
−
R
'
). Show that this is the case.
Oasis B is 9.0km due east of oasis A. Starting from oasis A, a camel walks 20 km in a direction
15.0° south of east and then
walks 34 km due north. If it is to then walk directly to B, (a) how far and (b) in what direction
(relative to the positive x-axis within the range (-180°, 180°]) should it walk?
Gruen data : Distance between A AND B'is d = 9,0 Km
Please Note:
step I
step 2
all the answeRs are
correct,
The vector diagram of displacement of camel is shown below.
A From step 4 (b)
Please explain (Cindetail
Why y ou use the 270°
Qnd - tan () insteod
of ton" )
Theunk jou!
N
R
d2
W-
B
E
C
E
In above figure:
Step 4
d, = 20 km
(а)
d, = 34 km
The distance travelled by the camel to reach the oasis B is:
JBC + DC
DB =
Step 3
(10.318 km ) +(28.823 km )*
= 30.6 km
From geometrical property:
(b) * Explaruthion, Please
BC = AC – AB
= d̟ cos15° - d
= (20 km ) cos15° – 9.0 km 0 = 270° – ZCDB
= 10.318 km
The direction of displacement relative to positive x-axis is
ВС
= 270°- tan
DC
DC = DE - CE…
B = -i - 4j
and
47.
For
vectors
A = -3 i – 2j, calculate (a) A + B and its
magnitude and direction angle, and (b) Á - B and its
magnitude and direction angle.
At a football game, imagine the line of scrimmage is the y-axis. A player, starting at the y-axis, runs 9.00 yards, back (in the −x-direction), then 15.0 yards parallel to the y-axis (in the −y-direction). He then throws the football straight downfield 40.0 yards in a direction perpendicular to the y-axis (in the +x-direction). What is the magnitude of the displacement (in yards) of the ball?
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