Chapter 3, Problem 60GP

To determine

To find: Time of flight of Olympic long jumper.Maximum height of Olympic long jumper.

Answer to Problem 60GP

0.87 sec

0.94 m.

Explanation of Solution

Given:

Range, R = 8m

Speed, u = 9.1 m/s

Formula Used:

  $\begin{array}{l}R=\frac{2u{u}_y}{g}\\ T=\frac{2u_y}{g}\\ H=\frac{u_y^2}{2g}\end{array}$

Calculation:

Substituting the given value

  $\begin{array}{l}8=\frac{24\times u_y}{10}\\ u_y=4.3\text{ m/s}\end{array}$

Substituting the given value

  $T=\frac{2\times 43}{10}=0.87\text{ sec}$

Substituting the value, to find the height,

  $\begin{array}{l}H=\frac{4.3\times 4.3}{2\times 10}\\ H=0.94\text{m}\end{array}$

Conclusion:

The maximum height is 0.94 m.

The time for which the long jumper is in air is 0.87 sec.