Chapter 3, Problem 45P

(a)

To determine

The speed of the water

Answer to Problem 45P

1.24 m/s

Explanation of Solution

Given:

  $\begin{array}{l}\text{Velocity of boat;}{v}_b=2.60\text{ m/s}\\ \text{Angle, }\theta \text{= 28}\text{.5°}\end{array}$

Formula Used:

  $v_y=v_b\sin \theta$

Calculation:

Consider the given situation.

  

  

Substituting the given values

  $\begin{array}{l}{v}_b\sin \theta =v_{\text{water}}\\ v_{\text{water}}=2.60\sin \left(28.5\right)\\ v_{\text{water}}=1.24\text{ m/s}\end{array}$

Conclusion:

Thus, the speed of water is 1.24 m/s

(b)

To determine

Speed of boat with respect to shore.

Answer to Problem 45P

2.28 m/s

Explanation of Solution

Given:

  $\begin{array}{l}\text{Velocity of boat;}{v}_b=2.60\text{ m/s}\\ \text{Angle, }\theta \text{= 28}\text{.5°}\end{array}$

Formula Used:

  $v=v_b\cos \theta$

Calculation:

Substituting the value

  $\begin{array}{l}v=2.60\cos 28.5\\ v=2.28\text{ m/s}\end{array}$

Conclusion:

The speed of boat is 2.28 m/s.